To find the area $A$ of a trapezoid, we use the formula:

$A = \frac{1}{2} \times (b_1 + b_2) \times h$

Where:

• $b_1 = 4.13 \, \text{m}$ (one base),
• $b_2 = 9.07 \, \text{m}$ (the other base),
• $h = 5.6 \, \text{m}$ (height).

Now we substitute the values into the formula:

$A = \frac{1}{2} \times (4.13 + 9.07) \times 5.6$

First, calculate the sum of the bases:

$4.13 + 9.07 = 13.2 \, \text{m}$

Then, multiply by the height:

$A = \frac{1}{2} \times 13.2 \times 5.6 = \frac{1}{2} \times 73.92 = 36.96 \, \text{m}^2$

Thus, the area $A$ of the trapezoid is 36.96 m², but this is not among the given options. However, you mentioned different units (cm² and m²) in the choices, so we should ignore choices in cm², as the area calculation fits $\text{m}^2$.

Would you like to ask more details or verify anything? Here are 5 relative questions to explore:

1. What if one of the bases is unknown? How would we find it?
2. How would the formula change for a trapezoid with non-parallel sides?
3. Can you explain the steps to convert between m² and cm²?
4. How would you calculate the perimeter of the same trapezoid?
5. What happens to the area if the height is halved?

Tip: Always check unit consistency when solving geometric problems!