Find the missing dimension of the trapezoid

5. If a = b1 and b = b2.

a = 4.13 m, b = 9.07 m, h = 5.6 m, A =  blank

 


15.33 cm^2 100 cm^2 73.92 m^2 24.485 cm^2 24 cm^2

To find the area \( A \) of a trapezoid, we use the formula:

\[
A = \frac{1}{2} \times (b_1 + b_2) \times h
\]

Where:
- \( b_1 = 4.13 \, \text{m} \) (one base),
- \( b_2 = 9.07 \, \text{m} \) (the other base),
- \( h = 5.6 \, \text{m} \) (height).

Now we substitute the values into the formula:

\[
A = \frac{1}{2} \times (4.13 + 9.07) \times 5.6
\]

First, calculate the sum of the bases:

\[
4.13 + 9.07 = 13.2 \, \text{m}
\]

Then, multiply by the height:

\[
A = \frac{1}{2} \times 13.2 \times 5.6 = \frac{1}{2} \times 73.92 = 36.96 \, \text{m}^2
\]

Thus, the area \( A \) of the trapezoid is **36.96 m²**, but this is not among the given options. However, you mentioned different units (cm² and m²) in the choices, so we should ignore choices in cm², as the area calculation fits \( \text{m}^2 \).

Would you like to ask more details or verify anything? Here are 5 relative questions to explore:

1. What if one of the bases is unknown? How would we find it?
2. How would the formula change for a trapezoid with non-parallel sides?
3. Can you explain the steps to convert between m² and cm²?
4. How would you calculate the perimeter of the same trapezoid?
5. What happens to the area if the height is halved?

**Tip:** Always check unit consistency when solving geometric problems!

Find the missing dimension of the trapezoid. a = b1 and b = b2. a = 4.13 m, b = 9.07 m, h = 5.6 m, A = blank. Options: 15.33 cm^2, 100 cm^2, 73.92 m^2, 24.485 cm^2, 24 cm^2

Learn how to calculate the area of a trapezoid with bases 4.13 m and 9.07 m, and height 5.6 m. This geometry problem walks through the formula A = (1/2) × (b1 + b2) × h, leading to an area of 36.96 m². Suitable for Grades 6-8, with a focus on geometric concepts and unit consistency.

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