Math Problem Statement

In trapezium ADCB, AD is parallel to BC, and PQ joins the mid-points of AD and BC. M is a point on PQ such that PM = 4.MQ. If the area of triangle AMB is 24 square units, find the area of triangle CMD.

Solution

The problem involves a trapezium ADCBADCB, with parallel sides ADBCAD \parallel BC, and a line PQPQ joining the midpoints of ADAD and BCBC.

We are given:

  • MM is a point on PQPQ, and PM=4×MQPM = 4 \times MQ.
  • The area of AMB=24sq. units\triangle AMB = 24 \, \text{sq. units}.
  • We need to find the area of CMD\triangle CMD.

Step-by-step approach:

  1. Trapezium Symmetry: Since PQPQ joins the midpoints of ADAD and BCBC, and ADBCAD \parallel BC, the trapezium has symmetric properties that help in dividing the larger trapezium into smaller triangles.

  2. Ratio of Segments PMPM and MQMQ: The ratio of PM:MQ=4:1PM : MQ = 4:1, meaning MM divides PQPQ in this ratio.

  3. Area Proportionality: The triangles formed by diagonals in such configurations are proportional to the segments dividing the diagonals and parallel lines. The ratio of the areas of AMB\triangle AMB and CMD\triangle CMD will be affected by the ratio of the segment lengths since the triangles share common heights (from point MM perpendicular to base PQPQ).

  4. Area Calculation:

    • PM:MQ=4:1PM : MQ = 4:1, so the areas of triangles on each side of MM will also be in this ratio. Let the area of CMD\triangle CMD be xx.
    • Using the area of AMB=24sq. units\triangle AMB = 24 \, \text{sq. units}, we can set up the equation: Area of AMBArea of CMD=41\frac{\text{Area of } \triangle AMB}{\text{Area of } \triangle CMD} = \frac{4}{1} 24x=4\frac{24}{x} = 4 Solving this gives: x=244=6sq. units.x = \frac{24}{4} = 6 \, \text{sq. units}.

Thus, the area of CMD\triangle CMD is 6 square units.

Would you like more details or have any further questions? Here are some related questions:

  1. How does the midline theorem apply in trapezium geometries like this?
  2. Why does the ratio of areas depend on the ratio of segment lengths for triangles with a common height?
  3. What would happen if the ratio PM:MQPM:MQ was different? How would that affect the areas?
  4. How can we verify if the area of AMB\triangle AMB is correct using coordinates or another method?
  5. What other geometric properties can be derived from the trapezium's symmetry?

Tip: In problems involving trapeziums and midlines, always consider the properties of parallel lines and proportionality, as they simplify area and length calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Trapezium
Proportionality of Areas

Formulas

Area of a triangle = 0.5 * base * height

Theorems

Midline Theorem
Area proportionality in triangles

Suitable Grade Level

Grades 9-10