Hello! I see you uploaded a photo with a math question related to the area of a trapezium. The problem asks to find the area of the trapezium-shaped surface of a table. The parallel sides of the trapezium are given as 1 m and 1.2 m, and the perpendicular distance (height) between them is 0.8 m.

The formula to calculate the area $A$ of a trapezium is:

$A = \frac{1}{2} \times (a + b) \times h$

Where:

• $a$ and $b$ are the lengths of the parallel sides,
• $h$ is the height (perpendicular distance between the parallel sides).

Substituting the given values:

• $a = 1 \, \text{m}$,
• $b = 1.2 \, \text{m}$,
• $h = 0.8 \, \text{m}$.

$A = \frac{1}{2} \times (1 + 1.2) \times 0.8$ $A = \frac{1}{2} \times 2.2 \times 0.8$ $A = 0.5 \times 1.76 = 0.88 \, \text{m}^2$

Thus, the area of the trapezium is $0.88 \, \text{m}^2$.

Would you like more details or have any other questions?

Here are 5 related questions:

1. What is the formula for the perimeter of a trapezium?
2. How would the area change if the height were doubled?
3. Can you calculate the area if one of the parallel sides is unknown?
4. How is the area of a trapezium related to the area of a rectangle?
5. What if the trapezium was rotated? Does the area depend on orientation?

Tip: When working with trapeziums, always ensure you're correctly identifying the parallel sides to use in the area formula!