To transpose the equation \( q = \frac{3p}{2} - 4 \) and make \( p \) the subject, follow these steps:

1. **Add 4 to both sides** to eliminate the constant on the right-hand side:
   \[
   q + 4 = \frac{3p}{2}
   \]

2. **Multiply both sides by 2** to remove the fraction:
   \[
   2(q + 4) = 3p
   \]

3. **Divide both sides by 3** to solve for \( p \):
   \[
   p = \frac{2(q + 4)}{3}
   \]

So, the equation with \( p \) as the subject is:
\[
p = \frac{2(q + 4)}{3}
\]

Would you like further details on any step? 

Here are some related questions:
1. How do you solve for \( p \) if \( q \) is given?
2. Can you simplify the equation for different values of \( q \)?
3. What happens if the equation has different constants, e.g., \( q = \frac{5p}{3} - 7 \)?
4. How would you solve the equation if there was a square or square root involved?
5. How can this method be applied to more complex algebraic equations?

**Tip:** When transposing equations, always perform the same operation on both sides to maintain equality.

Learn how to transpose the equation q = (3p / 2) - 4 to solve for p with a step-by-step solution. This problem covers key algebraic concepts, including linear equations and solving for variables. Suitable for students in Grades 7-9.

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