Math Problem Statement

A sum of rupees 9510 is made up of 50 2010 and 5 rupees note the number of 10 rupees note 8 21.31 of the number of Rs 50 note 42 upon 37 of the number of 5 rupees notes and 4 by 5 of the number of 20 rupees note find the sum of the number of notes of each denomination

Solution

We are tasked with finding the total number of notes for each denomination and their respective counts, given the following information:

  1. The total sum is ₹9510.
  2. The denominations involved are ₹10, ₹20, ₹50, and ₹5.
  3. Relationships between the numbers of notes of different denominations are provided as:
    • The number of ₹10 notes is 21.311\frac{21.31}{1} times the number of ₹20 notes .

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Math Problem Analysis

Mathematical Concepts

Algebra
Ratio and Proportion
Linear Equations

Formulas

Total sum = (Number of ₹10 notes × 10) + (Number of ₹20 notes × 20) + (Number of ₹50 notes × 50) + (Number of ₹5 notes × 5)
Relationships: n₁ = k × n₂ (where k is a given ratio)

Theorems

Proportionality Theorem

Suitable Grade Level

Grades 9-12

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