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The problem you shared from the image is as follows:

**Problem:**  
A purse contains ₹250 in notes of denominations ₹10 and ₹50. If the number of ₹10 notes is one more than that of ₹50 notes, find the number of notes of each denomination.

### Solution:

Let the number of ₹50 notes be **x**.

- The number of ₹10 notes is **x + 1** (as given in the problem).

Now, let's form an equation based on the total amount:

- The value of ₹50 notes = \( 50 \times x \)
- The value of ₹10 notes = \( 10 \times (x + 1) \)

According to the problem, the total value of these notes is ₹250. Therefore, the equation becomes:
\[
50x + 10(x + 1) = 250
\]

Now, solve this equation:

1. Expand the equation:
\[
50x + 10x + 10 = 250
\]

2. Combine like terms:
\[
60x + 10 = 250
\]

3. Subtract 10 from both sides:
\[
60x = 240
\]

4. Divide by 60:
\[
x = 4
\]



A purse contains ₹250 in notes of denominations ₹10 and ₹50. If the number of ₹10 notes is one more than that of ₹50 notes, find the number of notes of each denomination.

Learn how to solve a linear equation problem involving ₹10 and ₹50 notes, where the total value is ₹250, and the number of ₹10 notes is one more than ₹50 notes. Suitable for students in Grades 8-10.

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