Math Problem Statement

The current supplied by a battery slowly decreases as the battery runs down. Suppose that the current as a function of time is I = ( 0.860 A ) e−t/6hr .What is the total number of electrons transported from the positive electrode to the negative electrode by the charge escalator from the time the battery is first used until it is completely dead?

Solution

To find the total number of electrons transported from the positive electrode to the negative electrode, we need to calculate the total charge QQ transported by the current over the time period from when the battery is first used until it is completely dead.

The current is given by:

I(t)=(0.860A)et/6hrI(t) = (0.860 \, \text{A}) \, e^{-t/6 \, \text{hr}}

Step 1: Express Current in SI Units

Since the current is in amperes, and time is in hours, we need to convert time into seconds to use standard SI units. The time constant here is 6hr=6×3600s=21600s6 \, \text{hr} = 6 \times 3600 \, \text{s} = 21600 \, \text{s}.

Thus, the current equation becomes:

I(t)=(0.860A)et/21600sI(t) = (0.860 \, \text{A}) \, e^{-t/21600 \, \text{s}}

Step 2: Total Charge Transported

The total charge transported QQ is the integral of the current

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Exponential Decay
Integration
Electric Charge
Current

Formulas

I(t) = (0.860 A) e^(-t/21600 s)
Q = ∫ I(t) dt
Q = ne (Charge transported by n electrons)

Theorems

Fundamental Theorem of Calculus (for integration)

Suitable Grade Level

Undergraduate Level (Physics/Mathematics)