Math Problem Statement
Solution
To solve this problem, let’s break it down step-by-step using the information provided:
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Given Information:
- A sum of money becomes four times itself in 10 years under simple interest.
- We are asked to find in how many years the same sum of money will become three times itself at the same interest rate.
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Setting Up the Problem:
- Let the principal (initial sum) be .
- According to the problem, in 10 years, the amount becomes , which means the interest earned is .
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Calculating the Rate of Interest:
- Since simple interest where is the rate per annum and is the time in years.
- We know that and years, so:
- Dividing both sides by (assuming ):
- Solving for :
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Finding the Time to Become Three Times Itself:
- Now, we want the money to become three times itself, meaning the amount should be .
- The interest earned in this case would be .
- Using the simple interest formula again, we have:
- Dividing both sides by :
- Solving for :
Answer: The money will become three times itself in years or approximately 6 years and 8 months.
Would you like more details or explanations on any part of this solution?
Related Questions:
- What would the time be if the money had to become five times itself?
- How would the solution change if compound interest was used instead?
- Can you explain how to determine the rate of interest in more detail?
- What is the formula for simple interest, and why is it applicable here?
- How does changing the rate of interest affect the time taken for the sum to triple?
Tip:
For simple interest problems, remember that the interest grows linearly with time, which makes it easier to calculate for whole-number multiples of the principal.
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Math Problem Analysis
Mathematical Concepts
Simple Interest
Algebra
Formulas
Simple Interest (SI) = Principal (P) × Rate (R) × Time (T)
Total Amount = Principal + Simple Interest
Theorems
Direct Proportion in Simple Interest
Suitable Grade Level
Grades 8-10
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