Math Problem Statement

The inner square is enclosed by a larger square. What is the area of the inner square? Start by writing a subtraction equation you could use to find the area of the inner square. One square is tilted inside of another larger square. The inner square sits inside the outer square so that it cuts each side of the outer square into two pieces, one 3 units long and the other 2 units long.

area of outer square

area of inner square

sum of the areas of the 4 triangles You got it! Use the equation to find the area of the inner square. Start by finding the area of the outer square. One square is tilted inside of another larger square. The inner square sits inside the outer square so that it cuts each side of the outer square into two pieces, one 3 units long and the other 2 units long.area of outer square - sum of the areas of the 4 triangles = area of inner square units 2 - = ?

Solution

Let's break this down step by step!

Step 1: Understanding the Situation

You have a larger square, and inside it, there is a smaller, tilted square (the inner square). The inner square intersects each side of the outer square, creating two segments of each side: one segment is 3 units long, and the other is 2 units long. So, each side of the outer square is divided into two parts: one of length 3 and the other of length 2.

This means the total length of each side of the outer square is:

3+2=5 units3 + 2 = 5 \text{ units}

Step 2: Finding the Area of the Outer Square

The area of a square is given by the formula:

Area of a square=(side length)2\text{Area of a square} = (\text{side length})^2

For the outer square, with side length 5 units, the area is:

Area of outer square=52=25 square units\text{Area of outer square} = 5^2 = 25 \text{ square units}

Step 3: Area of the 4 Triangles

We need to determine the area of the four triangles that are formed between the inner square and the outer square. Each triangle is right-angled, and the two segments (3 units and 2 units) form the legs of the triangle. The area of one triangle is:

Area of one triangle=12×base×height\text{Area of one triangle} = \frac{1}{2} \times \text{base} \times \text{height}

For each triangle, the base is 3 units and the height is 2 units, so the area of one triangle is:

Area of one triangle=12×3×2=3 square units\text{Area of one triangle} = \frac{1}{2} \times 3 \times 2 = 3 \text{ square units}

Since there are 4 triangles, the total area of the triangles is:

Total area of 4 triangles=4×3=12 square units\text{Total area of 4 triangles} = 4 \times 3 = 12 \text{ square units}

Step 4: Finding the Area of the Inner Square

Now, using the equation:

Area of outer squareArea of 4 triangles=Area of inner square\text{Area of outer square} - \text{Area of 4 triangles} = \text{Area of inner square}

Substituting the known values:

2512=1325 - 12 = 13

So, the area of the inner square is 13 square units.

Final Answer:

Area of inner square=13 square units\text{Area of inner square} = 13 \text{ square units}


Would you like more details on how to approach these types of problems or any other questions?

Related Questions:

  1. How do we calculate the area of a right-angled triangle?
  2. What is the method to find the area of a square with a tilted position inside another square?
  3. How would this approach change if the triangles were not right-angled?
  4. If the side lengths of the outer square were different, how would the solution change?
  5. How can you find the side length of a square given its area?

Tip: When solving problems involving shapes inside other shapes, it often helps to break the figure into simpler components, like triangles and squares, and work from there.

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Math Problem Analysis

Mathematical Concepts

Geometry
Area of squares
Area of triangles
Subtraction in geometry

Formulas

Area of a square = (side length)^2
Area of a triangle = 1/2 * base * height

Theorems

Area of squares
Area of right-angled triangles

Suitable Grade Level

Grades 7-9