It appears that the image you uploaded contains a math problem involving the sale of concert tickets by students and adults. Here's the breakdown of the problem:

• Student tickets are sold for $5.
• Adult tickets are sold for $10.
• The total number of tickets sold is 85.
• The total revenue from the tickets is $800.

The problem is asking how many student tickets and adult tickets were sold.

Let:

• $x$ be the number of student tickets sold.
• $y$ be the number of adult tickets sold.

We can write two equations based on the given information:

1. $x + y = 85$ (since the total number of tickets sold is 85)
2. $5x + 10y = 800$ (since the total revenue is $800, with student tickets contributing $5 each and adult tickets contributing $10 each)

Solving the system of equations:

From the first equation, solve for $y$: $y = 85 - x$

Substitute $y = 85 - x$ into the second equation: $5x + 10(85 - x) = 800$

Now, simplify and solve for $x$: $5x + 850 - 10x = 800$ $-5x + 850 = 800$ $-5x = 800 - 850$ $-5x = -50$ $x = 10$

Now substitute $x = 10$ back into the first equation: $10 + y = 85$ $y = 85 - 10$ $y = 75$

Thus, the school sold:

• 10 student tickets,
• 75 adult tickets.

If you'd like further clarification or additional questions based on this, feel free to ask!

Follow-up questions:

1. How would the solution change if the prices for the tickets were reversed?
2. What if the total number of tickets sold was 90 instead of 85?
3. Can we solve this using matrix methods?
4. How can we verify the solution by checking the revenue?
5. What happens if you sell the tickets at different prices, say $6 for students and $12 for adults?

Tip: Always double-check your work by substituting the values you solve for back into the original equations to ensure they satisfy both conditions.