To solve the addition problem:

\[
(3 \ 9 \ 10) + (5 \ 1 \ 2)
\]

We can add the corresponding digits from both sets:

1. Tens place: \( 10 + 2 = 12 \), so carry 1.
2. Ones place: \( 9 + 1 + 1 (carry) = 11 \), so carry 1.
3. Hundreds place: \( 3 + 5 + 1 (carry) = 9 \).

Thus, the final result is **912**.

Would you like further details or have any questions?

Here are 5 related questions to expand your knowledge:
1. How would you handle addition if the sets had four digits each?
2. Can you perform subtraction for the same number sets?
3. How does addition change when dealing with negative numbers?
4. How would this process look if decimals were involved?
5. Can you explain the process of carrying numbers in addition?

**Tip:** Always align digits by place value when performing addition or subtraction!

Explore the detailed step-by-step solution to the three-digit addition problem: 391 + 512. This problem emphasizes the importance of place value and carrying over in basic arithmetic, suitable for students in Grades 3-4.

Math Problem Statement

3 9 10 + 5 1 2

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