To find the theoretical probability of flipping a heads and then rolling a dice and getting a 2, we need to calculate the probability of each independent event:

1. Probability of flipping a heads: Since a coin has two sides, the probability of flipping a heads is: $P(\text{Heads}) = \frac{1}{2}$

2. Probability of rolling a 2 on a six-sided die: Since a die has 6 faces, the probability of rolling a 2 is: $P(\text{Rolling a 2}) = \frac{1}{6}$

Since these two events (flipping a coin and rolling a die) are independent, the total probability of both events occurring in sequence (flipping heads and then rolling a 2) is the product of their individual probabilities: $P(\text{Heads and Rolling a 2}) = P(\text{Heads}) \times P(\text{Rolling a 2}) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}$

Thus, the theoretical probability of flipping heads and then rolling a 2 is $\frac{1}{12}$.

Would you like more details or have any other questions?

---

Here are 5 related questions to expand on this:

1. What is the probability of flipping tails and then rolling a 4?
2. How would the probability change if the die had 8 sides?
3. What is the probability of flipping two heads in a row?
4. What is the probability of rolling an odd number on the die?
5. How would you calculate the probability of flipping a heads and rolling an odd number?

Tip: When calculating probabilities of independent events, always multiply the individual probabilities together.