To solve the problem, we analyze the events step-by-step:

1. Coin Toss: A coin has two outcomes: Head (H) and Tail (T).

   • Probability of getting a Head = $\frac{1}{2}$.

2. Die Roll: A standard die has six outcomes: {1, 2, 3, 4, 5, 6}.

   • The numbers greater than 1 are {2, 3, 4, 5, 6}.
   • Probability of rolling a number greater than 1 = $\frac{5}{6}$.

3. Combined Event: The events are independent, so the probability of both occurring (a head from the coin and a number greater than 1 from the die) is the product of their individual probabilities:

$P(\text{Head and Number > 1}) = P(\text{Head}) \times P(\text{Number > 1})$

$P(\text{Head and Number > 1}) = \frac{1}{2} \times \frac{5}{6} = \frac{5}{12}$

Final Answer:

The probability of getting a head and a number greater than 1 is $\frac{5}{12}$.

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Would you like further details or additional examples? Here are 5 related questions:

1. What is the probability of getting a tail and a number greater than 4?
2. What is the probability of getting a head and an odd number?
3. If the coin is biased with $P(\text{Head}) = 0.6$, how does the probability change?
4. What is the probability of getting a head or a number greater than 1?
5. How does the answer change if the die is replaced with a 10-sided die?

Tip: For combined events, always confirm whether they are independent before multiplying probabilities.