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The problem asks to determine the measure of \( \angle BAC \), where \( BC \) is the diameter of the circle, and points \( A \), \( B \), and \( C \) lie on the circle.

### Key Observation:
- Since \( BC \) is the diameter of the circle, any angle formed by a point on the circumference (like \( A \)) and the endpoints of the diameter (points \( B \) and \( C \)) will always be a right angle.
  
This is a direct consequence of the **Thales' Theorem**, which states that an angle inscribed in a semicircle is a right angle (i.e., \( 90^\circ \)).

### Solution:
Therefore, \( \angle BAC = 90^\circ \).

Would you like more details or have further questions?

Here are five related questions:
1. What is Thales' Theorem, and why does it apply here?
2. How do you calculate other angles in a circle given the diameter?
3. What are other properties of angles inscribed in a circle?
4. How do we prove that an inscribed angle in a semicircle is a right angle?
5. How do angles in a cyclic quadrilateral relate to each other?

**Tip:** Thales' Theorem is a key principle in circle geometry and can simplify many angle-related problems when the diameter is involved.

Tentukan besar \(\angle BAC\) pada lingkaran di mana ruas garis BC merupakan diameter lingkaran.

Solve the geometric problem involving a circle where BC is the diameter. Use Thales' Theorem to find that angle BAC is 90°. Suitable for students in Grades 7-9 studying circle theorems.

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