Math Problem Statement

To test the convergence of the series ∑��∑un​, where ��=1+2�1+3�un​=1+3n​1+2n​​, using partial sums, follow these steps:

Solution

To test the convergence of the series n=1un\sum_{n=1}^\infty u_n, where

un=1+3n1+2n,u_n = \frac{1 + 3n}{1 + 2n},

using partial sums, follow these steps:


Step 1: Understand the Partial Sum

The nn-th partial sum of the series is given by:

Sn=k=1nuk.S_n = \sum_{k=1}^n u_k.

This represents the sum of the first nn terms of the series.


Step 2: Express the General Term unu_n

The term unu_n is already defined as:

un=1+3n1+2n.u_n = \frac{1 + 3n}{1 + 2n}.

Simplify this term if possible to better analyze its behavior, but here it is already in reduced form.


Step 3: Analyze the Behavior of unu_n

Examine whether un0u_n \to 0 as nn \to \infty, a necessary condition for the convergence of a series. Compute:

limnun=limn1+3n1+2n.\lim_{n \to \infty} u_n = \lim_{n \to \infty} \frac{1 + 3n}{1 + 2n}.

Using the leading terms in the numerator and denominator, we find:

limnun=32.\lim_{n \to \infty} u_n = \frac{3}{2}.

Since un320u_n \to \frac{3}{2} \neq 0, the series diverges.


Step 4: Confirm Using Partial Sums

Despite observing divergence based on the behavior of unu_n, compute the partial sums SnS_n:

Sn=k=1n1+3k1+2k.S_n = \sum_{k=1}^n \frac{1 + 3k}{1 + 2k}.

This involves summing a sequence of rational terms, but because unu_n does not approach zero, the partial sums SnS_n grow unbounded.


Step 5: Conclude the Convergence

Since un320u_n \to \frac{3}{2} \neq 0, the necessary condition for convergence is not satisfied. Therefore, the series n=1un\sum_{n=1}^\infty u_n diverges.


Do you want a step-by-step derivation of the partial sums SnS_n, or would you like to explore similar problems? 😊


Follow-Up Questions

  1. What does the divergence test state, and how does it relate to this problem?
  2. How can one simplify expressions for general terms to analyze limits efficiently?
  3. What is the difference between absolute and conditional convergence?
  4. How do geometric and harmonic series compare to this example in terms of convergence?
  5. What role does the growth rate of numerator and denominator play in determining series behavior?

Tip: Always check if the term un0u_n \to 0 as nn \to \infty; it’s a quick test to rule out convergence!

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Partial Sums
Limit of a Sequence
Rational Functions

Formulas

S_n = ∑(k=1 to n) u_k
u_n = (1 + 3n) / (1 + 2n)
lim (n -> ∞) u_n = (3 / 2)

Theorems

Test for Divergence
Necessary Condition for Convergence of Series

Suitable Grade Level

Grades 11-12 (College Prep)