Math Problem Statement

Two blocks are connected by a massless string and are held in position by another massless string along a frictionless incline (as shown in the figure). Let M1 = 6.30 kg, M2 = 5.30 kg, and θ = 17.0°. Calculate the tension in the string connecting the two blocks.

Solution

In this problem, we are dealing with two blocks connected by a string, with the entire system resting on a frictionless incline. We'll calculate the tension in the string connecting the two blocks.

Step 1: Free Body Diagram and Forces

For both blocks, the forces acting on them include:

  1. The gravitational force Fg=mgF_g = mg acting vertically downwards.
  2. The normal force NN perpendicular to the surface of the incline.
  3. The tension in the string between the blocks (which we need to find).
  4. The component of gravitational force parallel to the incline, which causes the blocks to slide.

Gravitational Force Components:

For each block, the component of the gravitational force along the incline is given by: Fgravity, parallel=mgsinθF_{\text{gravity, parallel}} = mg \sin \theta where θ=17.0\theta = 17.0^\circ, M1=6.30kgM_1 = 6.30 \, \text{kg}, and M2=5.30kgM_2 = 5.30 \, \text{kg}.

Step 2: Equation of Motion

Since the blocks are held in equilibrium (by the second string), the system is not moving. Therefore, the net force along the incline is zero for both blocks.

For Block 1 (M1M_1):

The forces acting on Block 1 along the incline are:

  • Tension TT pulling it upward along the incline (due to the string connecting it to Block 2).
  • The component of gravity pulling it downward along the incline.

Thus, for Block 1: T=M1gsinθT = M_1 g \sin \theta

For Block 2 (M2M_2):

Block 2 is also in equilibrium, with the tension TT pulling it upward and the component of gravity pulling it downward.

T=M2gsinθT = M_2 g \sin \theta

Step 3: Calculate the Tension

Now, let's calculate the tension in the string connecting the two blocks.

T=M2gsinθT = M_2 g \sin \theta

We know:

  • M2=5.30kgM_2 = 5.30 \, \text{kg}
  • g=9.8m/s2g = 9.8 \, \text{m/s}^2
  • θ=17.0\theta = 17.0^\circ

Now, we compute the tension.The tension in the string connecting the two blocks is approximately 15.19N15.19 \, \text{N}.

Would you like further details on the calculations, or do you have any questions?

Here are 5 related questions you might consider:

  1. How would the tension change if the angle of the incline increased?
  2. What happens to the tension if the masses of the blocks were equal?
  3. How would the problem change if there were friction on the incline?
  4. What would the tension be if only one block were on the incline?
  5. How can we calculate the normal force acting on each block?

Tip: Always check if there is any friction on the incline before assuming a frictionless scenario.

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Math Problem Analysis

Mathematical Concepts

Newton's Laws of Motion
Equilibrium
Force Components

Formulas

F_gravity_parallel = mg sin(θ)
T = M2 * g * sin(θ)

Theorems

Newton's Second Law
Equilibrium Condition

Suitable Grade Level

Grades 11-12 (High School Physics)