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In this problem, we have two bodies: one with a mass of 20 kg and another with a mass of 10 kg. The question asks for the tension in the rope from which the 10 kg body is suspended.

Let's analyze it step by step.

### Step 1: Forces on the 10 kg body
The 10 kg body experiences two forces:
- Its weight: \( W = m \cdot g \)
  Where:
  - \( m = 10 \, \text{kg} \)
  - \( g = 9.8 \, \text{m/s}^2 \) (acceleration due to gravity)
  
So, the weight of the 10 kg body is:
\[
W = 10 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 98 \, \text{N}
\]
Thus, the tension in the rope supporting the 10 kg body is **98 N** because it must balance the weight of the 10 kg mass.

### Answer:
The correct choice is **a. 98 N**.

Would you like more details or further explanation on this? Here are five related questions that expand on this concept:

1. How would the tension change if the mass of the second body were increased?
2. What would happen to the tension if the gravitational force on the planet changed?
3. How do we calculate the tension in a rope if the system is accelerating upward?
4. What if there were an additional mass hanging below the 10 kg mass? How would that affect the tension in the rope?
5. Could you explain how to calculate tension if the rope has mass?

**Tip:** Always draw a free-body diagram when dealing with forces in mechanics to visualize all acting forces clearly!

A body of mass 20 kg is suspended from the ceiling and a body of mass 10 kg is suspended below it. The tension in the rope from which the 10 kg body is suspended is:

Learn how to calculate the tension in a rope when a body of 10 kg is suspended below another body of 20 kg. This detailed solution uses Newton's Second Law and the weight formula W = m * g, with step-by-step guidance on solving for the tension. Suitable for high school physics students (Grades 9-12).

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