Math Problem Statement
Solution
The problem describes a system with two blocks connected by a rope passing over a pulley. One block with a weight of is on a table, while the other block with a weight of hangs vertically. We are tasked with finding:
(a) The acceleration of both blocks. (b) The tension in the rope.
Given:
- Weight of the block on the table:
- Weight of the hanging block:
- Gravitational acceleration:
- Ignore friction.
Step 1: Find the masses of both blocks
The mass of an object can be calculated from its weight using the relation: For the block on the table ():
For the hanging block ():
Step 2: Set up the equations for the system
Let represent the tension in the rope and the acceleration of both blocks. Since the system is connected by a rope, the blocks will share the same acceleration magnitude, but in opposite directions.
For the block on the table (): For the hanging block (), the forces acting are the tension upward and the weight downward. Therefore, applying Newton's second law:
Step 3: Solve the system of equations
We now have two equations:
Substitute into the second equation:
Rearrange to solve for acceleration : Substitute the known values:
Step 4: Find the tension in the rope
Now that we have the acceleration, substitute it back into the equation :
Final Answers:
(a) The acceleration of both blocks is .
(b) The tension in the rope is .
Would you like further details or explanations? Here are 5 related questions for deeper exploration:
- What happens if we introduce friction between the block and the table?
- How would the system behave if the hanging block were heavier than the block on the table?
- Can this system reach equilibrium, and if so, under what conditions?
- How does changing the mass of one of the blocks affect the tension in the rope?
- How would the acceleration change if the pulley had significant mass?
Tip: Always double-check whether external forces like friction or air resistance are present, as they can significantly change the results.
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Math Problem Analysis
Mathematical Concepts
Newton's Second Law
Free Body Diagrams
Kinematics
Dynamics
Formulas
F = ma
T = m_1 * a
m_2 * g - T = m_2 * a
a = (m_2 * g) / (m_1 + m_2)
Theorems
Newton's Second Law of Motion
Suitable Grade Level
Grades 10-12
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