Math Problem Statement
A block of mass 6 kg resting on a horizontal surface is connected by a cord passing over a light, frictionless pulley to a hanging block of mass 4 kg. The coefficient of kinetic friction between the block and the horizontal surface is 0.5. After the blocks are released find: (a) the acceleration of each block (b) The tension on the cord
Solution
To solve this problem, let’s denote the following variables for convenience:
- : mass of the block on the horizontal surface.
- : mass of the hanging block.
- : coefficient of kinetic friction between and the horizontal surface.
- : acceleration due to gravity.
Step 1: Identify the Forces on Each Block
For Block on the Horizontal Surface:
- Gravitational force: .
- Normal force (equal to gravitational force since it's on a horizontal surface): .
- Frictional force opposing motion: .
- Tension in the cord: (this is unknown and is the same on both blocks since the pulley is light and frictionless).
For Block (the Hanging Block):
- Gravitational force: .
- Tension in the cord: .
Step 2: Set Up the Equations of Motion
The system accelerates in the direction of the hanging block, so we can apply Newton’s Second Law for each block.
For :
Substituting :
For :
Substituting :
Step 3: Solve for Acceleration and Tension
Add Equations 1 and 2 to eliminate :
Now, substitute into Equation 1 to find :
Final Answers:
- (a) The acceleration of each block is .
- (b) The tension on the cord is .
Would you like more details, or do you have any questions about this problem?
Related Questions
- How would changing the coefficient of kinetic friction affect the acceleration?
- What would happen if the mass of were increased?
- How does the tension in the cord compare to the weight of and ?
- If the pulley were not frictionless, how would it affect the system?
- What would the acceleration be if the surface were frictionless?
Tip:
In pulley problems, always start by analyzing forces on each mass separately and set up equations for each block using Newton's Second Law.
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Math Problem Analysis
Mathematical Concepts
Newton's Second Law
Frictional Force
Pulley Systems
Equilibrium of Forces
Formulas
F = ma
Frictional force F_f = μ_k * N
Gravitational force F_g = m * g
Tension and acceleration equations for pulley systems
Theorems
Newton's Second Law of Motion
Suitable Grade Level
Grades 11-12
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