Math Problem Statement
Solution
The problem is asking to find the interval of time over which the temperature , given by the function
is greater than 100°F.
Step-by-step approach:
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Set up the inequality: To find when the temperature is greater than 100°F, we set up the inequality:
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Isolate the fraction: Subtract 98.6 from both sides:
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Multiply both sides by to eliminate the denominator (since for all real ):
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Expand the right-hand side:
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Rearrange the inequality:
or
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Solve the quadratic inequality: First, solve the corresponding quadratic equation:
Use the quadratic formula:
Simplifying:
So the two solutions are:
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Interpret the solution: The quadratic inequality is satisfied between the roots. So, the temperature is over 100°F in the interval:
Final answer: The temperature was over 100°F between approximately 0.18 hours and 5.52 hours.
Would you like more details on any step or have additional questions?
Related questions:
- What is the significance of solving quadratic inequalities in real-world applications?
- How does the quadratic formula help in solving non-linear inequalities?
- Can this model for temperature change be applied to other types of illnesses?
- How would you graph this function to visualize the temperature changes?
- What are the methods to solve inequalities besides using the quadratic formula?
Tip:
When solving quadratic inequalities, always check the sign of the quadratic expression in the intervals determined by the roots to verify the solution's correctness.
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Math Problem Analysis
Mathematical Concepts
Algebra
Inequalities
Quadratic Equations
Formulas
T(t) = 8t / (t^2 + 1) + 98.6
Quadratic equation formula: ax^2 + bx + c = 0
Theorems
Quadratic formula
Suitable Grade Level
Grades 10-12
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