Math Problem Statement
Solution
The problem asks to determine how many ways 3 tasks can be assigned to a committee consisting of 4 men and 6 women, with the condition that both men and women are given tasks.
Step 1: General Overview
You have a total of 10 committee members, 4 of whom are men and 6 of whom are women. There are 3 tasks to be assigned, and the constraint is that both men and women must receive assignments.
Step 2: Task Distribution
For both men and women to receive tasks, at least 1 man and 1 woman must be assigned a task. This means there are two possible ways to split the tasks between men and women:
- Case 1: Assign 1 task to a man and 2 tasks to women.
- Case 2: Assign 2 tasks to men and 1 task to a woman.
Step 3: Counting the Assignments
We will use combinations to count the ways in which these tasks can be assigned.
Case 1: 1 man and 2 women get the tasks
- Choose 1 man from 4 men:
- Choose 2 women from 6 women:
- The tasks can be assigned to these 3 people in ways.
The total number of ways in this case is:
Case 2: 2 men and 1 woman get the tasks
- Choose 2 men from 4 men:
- Choose 1 woman from 6 women:
- The tasks can be assigned to these 3 people in ways.
The total number of ways in this case is:
Step 4: Total Number of Ways
Adding both cases together, the total number of ways to assign the tasks such that both men and women get assignments is:
Final Answer:
There are 576 ways to assign the 3 tasks so that both men and women receive assignments.
Would you like further details or have any questions about this process?
Here are 5 related questions for further exploration:
- What happens if there are no restrictions on the gender of the people who get the tasks?
- How would the solution change if there were 5 men and 5 women?
- What if 4 tasks needed to be assigned instead of 3?
- How does the factorial affect the total number of assignments?
- Can you derive the number of ways if the committee had 3 men and 7 women?
Tip: In combinatorics, when you're dealing with task assignments, remember to consider both the selection of participants and the arrangement of tasks carefully.
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Math Problem Analysis
Mathematical Concepts
Combinatorics
Permutations
Combinations
Formulas
Combination formula: C(n, r) = n! / (r!(n-r)!)
Permutation formula: P(n) = n!
Theorems
Basic principles of counting and distribution in combinatorics
Suitable Grade Level
Grades 10-12
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