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The question provided reads as follows:

**Question No. 53:**
"Suppose A is an inlet pipe and B is an outlet pipe connected to a tank. Pipe A completely fills the tank in 100 minutes. Pipe B empties the tank in 150 minutes. How much more time, in percentage, is necessary to fill an empty tank up to 75% of its capacity when both the pipes are operational in comparison to the situation when only the inlet pipe works?"

### Let's solve this step by step:

1. **Rate of Pipe A:**
   Pipe A can fill the tank in 100 minutes. So, the rate at which Pipe A fills the tank is:
   \[
   \text{Rate of Pipe A} = \frac{1}{100} \, \text{tank per minute}.
   \]

2. **Rate of Pipe B:**
   Pipe B can empty the tank in 150 minutes. So, the rate at which Pipe B empties the tank is:
   \[
   \text{Rate of Pipe B} = \frac{1}{150} \, \text{tank per minute}.
   \]

3. **Combined Rate when both pipes are working:**
   When both Pipe A (inlet) and Pipe B (outlet) are operational, their combined rate is:
   \[
   \text{Net rate} = \frac{1}{100} - \frac{1}{150} = \frac{3}{300} - \frac{2}{300} = \frac{1}{300} \, \text{tank per minute}.
   \]
   Therefore, when both pipes are operational, it fills the tank at the rate of \(\frac{1}{300}\) tank per minute.

4. **Time taken to fill 75% of the tank when both pipes are operational:**
   The time to fill 75% of the tank at this net rate is:
   \[
   \text{Time} = \frac{0.75 \, \text{tank}}{\frac{1}{300}} = 0.75 \times 300 = 225 \, \text{minutes}.
   \]

5. **Time taken to fill 75% of the tank with only Pipe A:**
   When only Pipe A is working, the time taken to fill 75% of the tank is:
   \[
   \text{Time} = \frac{0.75 \, \text{tank}}{\frac{1}{100}} = 0.75 \times 100 = 75 \, \text{minutes}.
   \]

6. **Percentage increase in time:**
   The percentage increase in time when both pipes are operational compared to when only Pipe A is working is:
   \[
   \text{Percentage increase} = \frac{225 - 75}{75} \times 100 = \frac{150}{75} \times 100 = 200\%.
   \]

### Final Answer:
The time taken to fill the tank up to 75% of its capacity when both pipes are operational is **200%** more compared to when only the inlet pipe works.

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Would you like further details on any part of this solution?

Here are 5 related questions for practice:
1. How much time would it take to fill the tank if Pipe A and Pipe B had equal rates of flow?
2. What would be the new net filling rate if Pipe B could empty the tank in 200 minutes?
3. How long would it take to fill the tank completely with both pipes working?
4. How does the system behave if the outlet pipe (Pipe B) is faster than the inlet pipe?
5. How would the percentage change if the tank needed to be filled to 50% instead of 75%?

**Tip:** In problems with multiple rates (like filling and emptying), always subtract the emptying rate from the filling rate when both actions occur simultaneously.

Suppose A is an inlet pipe and B is an outlet pipe connected to a tank. Pipe A completely fills the tank in 100 minutes. Pipe B empties the tank in 150 minutes. How much more time, in percentage, is necessary to fill an empty tank up to 75% of its capacity when both the pipes are operational in comparison to the situation when only the inlet pipe works?

Solve a tank problem involving an inlet pipe that fills a tank in 100 minutes and an outlet pipe that empties it in 150 minutes. Learn how to calculate the percentage increase in time to fill 75% of the tank when both pipes are working compared to just the inlet pipe.

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