Math Problem Statement

My hotel had a swimming pool, and I wanted to host a poolside party for my birthday. I wanted to fill the pool using three pipes. Two pipes (A and B) could fill the pool in 4 hours and 9 hours. Another pipe can empty the pool in 6 hours. By mistake I opened all three pipes at 3 pm and realised at 3.30 pm. So, I closed it. When would the pool be completely filled with water?

Solution

Let's break down the situation to find out when the pool would be completely filled with water.

Given:

  • Pipe A can fill the pool in 4 hours.
  • Pipe B can fill the pool in 9 hours.
  • Pipe C can empty the pool in 6 hours.

You opened all three pipes at 3:00 PM and closed them at 3:30 PM. Afterward, only the filling pipes (A and B) remain open.


Step 1: Work done by each pipe in 1 hour

  • Pipe A's rate of filling = 14\frac{1}{4} of the pool per hour.
  • Pipe B's rate of filling = 19\frac{1}{9} of the pool per hour.
  • Pipe C's rate of emptying = 16\frac{1}{6} of the pool per hour.

Step 2: Net rate of filling with all three pipes open

With all three pipes open, the net rate of filling is: Net rate=(14+1916)\text{Net rate} = \left( \frac{1}{4} + \frac{1}{9} - \frac{1}{6} \right) We need to simplify this:

14=0.25,190.111,160.167\frac{1}{4} = 0.25, \quad \frac{1}{9} \approx 0.111, \quad \frac{1}{6} \approx 0.167 Net rate=0.25+0.1110.167=0.194 (approximately).\text{Net rate} = 0.25 + 0.111 - 0.167 = 0.194 \text{ (approximately)}.

So, the net rate of filling when all three pipes are open is approximately 0.194 of the pool per hour.

Step 3: Work done in the first 30 minutes

In the first 30 minutes (or 0.5 hours), the amount of the pool filled with all three pipes open is: Amount filled=0.194×0.5=0.097 (approximately).\text{Amount filled} = 0.194 \times 0.5 = 0.097 \text{ (approximately)}. So, about 9.7% of the pool is filled in the first 30 minutes.

Step 4: Work done by pipes A and B after 3:30 PM

After 3:30 PM, only pipes A and B are open, and their combined rate is: Rate of A and B=14+19=9+436=1336 of the pool per hour.\text{Rate of A and B} = \frac{1}{4} + \frac{1}{9} = \frac{9 + 4}{36} = \frac{13}{36} \text{ of the pool per hour}.

Step 5: Remaining pool to fill

The remaining part of the pool to be filled is: 1 - 0.097 = 0.903 \text{ (or 90.3% of the pool)}.

The time required to fill the remaining part is: Time=0.9031336=0.903×36132.5 hours.\text{Time} = \frac{0.903}{\frac{13}{36}} = 0.903 \times \frac{36}{13} \approx 2.5 \text{ hours}.

Step 6: Time of completion

If you started the process at 3:00 PM, closed Pipe C at 3:30 PM, and then it took approximately 2.5 hours to fill the remaining pool, the pool would be fully filled at: 3:30PM+2.5hours=6:00PM.3:30 \, \text{PM} + 2.5 \, \text{hours} = 6:00 \, \text{PM}.

Conclusion:

The pool would be completely filled at approximately 6:00 PM.


Would you like further clarification, or have any specific questions? Here are a few related questions:

  1. How do you calculate rates when multiple pipes are working together?
  2. What if the pool had a different shape—would the filling time change?
  3. How would a delay in closing Pipe C affect the outcome?
  4. How can you calculate the total volume of water if the pool's size is known?
  5. What if Pipe C had a faster rate of emptying?

Tip: Always check the rates of flow (filling or emptying) carefully when working with systems involving multiple inlets and outlets.

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Math Problem Analysis

Mathematical Concepts

Rates of work
Time and work
Algebra

Formulas

Net rate of work = rate of filling pipes - rate of emptying pipe
Time to fill = remaining pool volume / net rate of filling

Theorems

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Suitable Grade Level

Grades 9-10