Math Problem Statement

32 L of water is poured into a water tank. If the tank is now 2/3 filled, how much water does the tank hold when full? Another problem involves 63 L of water removed, leaving 65% of the water left in the tank. Lastly, determine the amount of water in a tank at 1/2 full when given conditions about its partial fillings.

Solution

Let’s break down and solve each question clearly.

Question 3

32 L of water is poured into a water tank. If the tank is now 23\frac{2}{3} full, how much water does the tank hold when full?

Let the capacity of the tank be xx liters.

From the problem, 23×x=32\frac{2}{3} \times x = 32.

Step 1: Solve for xx: x=3223=32×32=48L.x = \frac{32}{\frac{2}{3}} = 32 \times \frac{3}{2} = 48 \, \text{L}.

Answer: The tank holds 48 liters when full.


Question 4

63 L of water was taken out of a water tank, and there is 65% of the water left. What is the original volume of the water tank?

Let the original volume of the tank be xx liters.

After 63 liters were removed, 65% of the tank remains: 0.65x=x63.0.65x = x - 63.

Step 1: Solve for xx: 0.65x=x63    x0.65x=63    0.35x=63.0.65x = x - 63 \implies x - 0.65x = 63 \implies 0.35x = 63. x=630.35=180L.x = \frac{63}{0.35} = 180 \, \text{L}.

Answer: The original volume of the tank is 180 liters.


Question 5

A tank is 16\frac{1}{6} full. When 440 liters of water is added, the tank is now 58\frac{5}{8} full. How much water will be in the tank when it is 12\frac{1}{2} full?

Let the capacity of the tank be xx liters.

Step 1: Calculate the difference in fullness: 5816.\frac{5}{8} - \frac{1}{6}. Finding a common denominator: 58=3048,16=848.\frac{5}{8} = \frac{30}{48}, \quad \frac{1}{6} = \frac{8}{48}. 5816=3048848=2248=1124.\frac{5}{8} - \frac{1}{6} = \frac{30}{48} - \frac{8}{48} = \frac{22}{48} = \frac{11}{24}.

This means 440 liters corresponds to 1124\frac{11}{24} of the tank.

Step 2: Solve for the tank’s capacity xx: 1124x=440    x=440×2411=960L.\frac{11}{24}x = 440 \implies x = \frac{440 \times 24}{11} = 960 \, \text{L}.

Step 3: Calculate the amount of water when the tank is 12\frac{1}{2} full: 12x=12×960=480L.\frac{1}{2}x = \frac{1}{2} \times 960 = 480 \, \text{L}.

Answer: The tank will contain 480 liters when it is 12\frac{1}{2} full.


Any questions or further clarifications?

Here are five related questions to expand your understanding:

  1. How can we generalize the formula for tank capacity in similar fraction problems?
  2. What are some real-world applications of these types of percentage or fraction problems?
  3. How would the approach change if additional information about the tank were given?
  4. Can you explain how to check for consistency in percentage-based problems?
  5. How can unit conversion affect calculations in problems involving capacity?

Tip: Always double-check for proper alignment of fractions and percentages to ensure accuracy!

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Math Problem Analysis

Mathematical Concepts

Fractions
Percentages
Algebra

Formulas

Volume from fractional capacity (e.g., x * fraction = volume)
Percentage conversion to fractions

Theorems

Basic proportional reasoning in percentages and fractions

Suitable Grade Level

Grades 6-8