Math Problem Statement
Solution
We are tasked with finding the tangential and normal components of the acceleration for a particle whose position is given by:
To find the tangential component and the normal component of the acceleration at , we will follow these steps:
1. Velocity
The velocity is the derivative of the position vector:
At :
2. Acceleration
The acceleration is the derivative of the velocity vector:
At :
3. Tangential Component
The tangential component of the acceleration is given by:
First, calculate the dot product :
Now, calculate the magnitude of :
Thus, the tangential component is:
4. Normal Component
The normal component of the acceleration is given by:
First, calculate the magnitude of :
Now, calculate :
5. Conclusion
The tangential component and the normal component .
Thus, the correct answer is (c) .
Would you like further details or have any questions?
Here are 5 related questions to explore:
- How do you find the unit tangent vector in vector calculus?
- What is the physical meaning of tangential and normal components of acceleration?
- How do you compute curvature from the position vector of a particle?
- How does the magnitude of velocity relate to tangential acceleration?
- Can the normal component of acceleration ever be zero?
Tip: When solving problems with vectors, always remember to differentiate each component individually and apply the chain rule when necessary.
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Math Problem Analysis
Mathematical Concepts
Vector Calculus
Tangential and Normal Acceleration
Derivatives
Formulas
Velocity: v(t) = dr(t)/dt
Acceleration: a(t) = dv(t)/dt
Tangential Component: a_T = (v(t) · a(t)) / |v(t)|
Normal Component: a_N = sqrt(|a(t)|^2 - a_T^2)
Theorems
Vector differentiation and the chain rule in calculus
Suitable Grade Level
Grades 11-12 or Undergraduate
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