Math Problem Statement
Consider the curve given by 3 y f x x x 3
a. Find the equation of the line tangent to the curve at the point (1,3) b. Find the line normal to the curve at the point (1,3)
Solution
We are given the curve and need to:
(a) Find the equation of the tangent line at the point
To find the equation of the tangent line at a given point, we need the slope of the tangent, which is the derivative of evaluated at the point .
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Find the derivative : Using basic differentiation rules:
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Evaluate the derivative at to find the slope of the tangent line: So, the slope of the tangent line at is .
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Use the point-slope form of the line equation: The point-slope form of the equation of a line is: where is the slope and is the point on the line. Here, and the point is , so:
Simplifying this: Therefore, the equation of the tangent line is .
(b) Find the equation of the normal line at the point
The normal line is perpendicular to the tangent line. If the slope of the tangent line is , then the slope of the normal line, , is the negative reciprocal:
Since the slope of the tangent line is 2, the slope of the normal line is:
Now, we use the point-slope form of the line equation again, with slope and the point :
Simplifying this: Therefore, the equation of the normal line is .
Summary of Results:
- The tangent line at is .
- The normal line at is .
Would you like further details or clarification on any of the steps? Here's a list of related questions for you to explore:
- How do you find the slope of the tangent to a curve?
- What is the geometric meaning of the normal line?
- How do you determine the derivative of more complex polynomial functions?
- How can you apply these concepts in real-world problems, like velocity or optimization?
- What are other forms of the equation of a line besides point-slope form?
Tip: Always double-check your differentiation and arithmetic when working with derivatives, as small errors in these steps can lead to incorrect results in both tangent and normal line equations!
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Math Problem Analysis
Mathematical Concepts
Calculus
Differentiation
Tangent and Normal Lines
Formulas
Derivative of a polynomial function: f'(x) = 3x^2 - 1
Point-slope form of a line: y - y_1 = m(x - x_1)
Slope of normal line: m_n = -1/m_t
Theorems
Fundamental Theorem of Calculus (derivatives)
Perpendicular lines have negative reciprocal slopes
Suitable Grade Level
Grades 11-12