Math Problem Statement

The equation x^7y - xy^7 = -9999990 implicitly defines y as a function of x in an open rectangle around the point (1, 10). Determine an equation for the line that is tangent to the solution set to the equation at the point (1, 10).

Solution

To solve this problem, we will follow these steps:

Step 1: Differentiate the given equation implicitly

The given equation is:

x7yxy7=9999990x^7y - xy^7 = -9999990

Implicit differentiation will involve both xx and yy, treating yy as a function of xx. Taking the derivative of both sides with respect to xx, we get:

ddx(x7y)ddx(xy7)=ddx(9999990)\frac{d}{dx}(x^7y) - \frac{d}{dx}(xy^7) = \frac{d}{dx}(-9999990)

Using the product rule (uv)=uv+uv(uv)' = u'v + uv':

ddx(x7y)=7x6y+x7dydx\frac{d}{dx}(x^7y) = 7x^6y + x^7\frac{dy}{dx} ddx(xy7)=y7+7xy6dydx\frac{d}{dx}(xy^7) = y^7 + 7xy^6\frac{dy}{dx}

Substituting these into the equation:

7x6y+x7dydx(y7+7xy6dydx)=07x^6y + x^7\frac{dy}{dx} - (y^7 + 7xy^6\frac{dy}{dx}) = 0

Simplify:

7x6y+x7dydxy77xy6dydx=07x^6y + x^7\frac{dy}{dx} - y^7 - 7xy^6\frac{dy}{dx} = 0

Group terms involving dydx\frac{dy}{dx}:

x7dydx7xy6dydx=y77x6yx^7\frac{dy}{dx} - 7xy^6\frac{dy}{dx} = y^7 - 7x^6y

Factor out dydx\frac{dy}{dx}:

dydx(x77xy6)=y77x6y\frac{dy}{dx}(x^7 - 7xy^6) = y^7 - 7x^6y

Solve for dydx\frac{dy}{dx}:

dydx=y77x6yx77xy6\frac{dy}{dx} = \frac{y^7 - 7x^6y}{x^7 - 7xy^6}


Step 2: Evaluate dydx\frac{dy}{dx} at the point (1,10)(1, 10)

Substitute x=1x = 1 and y=10y = 10 into the expression for dydx\frac{dy}{dx}:

dydx=1077(16)(10)177(1)(106)\frac{dy}{dx} = \frac{10^7 - 7(1^6)(10)}{1^7 - 7(1)(10^6)}

Simplify the numerator:

1077(16)(10)=1000000070=999999010^7 - 7(1^6)(10) = 10000000 - 70 = 9999990

Simplify the denominator:

177(1)(106)=17000000=69999991^7 - 7(1)(10^6) = 1 - 7000000 = -6999999

Thus:

dydx=99999906999999=107\frac{dy}{dx} = \frac{9999990}{-6999999} = -\frac{10}{7}


Step 3: Write the equation of the tangent line

The slope of the tangent line is 107-\frac{10}{7}, and the point of tangency is (1,10)(1, 10). The equation of a line is:

L(x)=y1+m(xx1)L(x) = y_1 + m(x - x_1)

Substitute y1=10y_1 = 10, m=107m = -\frac{10}{7}, and x1=1x_1 = 1:

L(x)=10107(x1)L(x) = 10 - \frac{10}{7}(x - 1)

Simplify:

L(x)=10107x+107L(x) = 10 - \frac{10}{7}x + \frac{10}{7}

Combine constants:

L(x)=707+107107x=807107xL(x) = \frac{70}{7} + \frac{10}{7} - \frac{10}{7}x = \frac{80}{7} - \frac{10}{7}x

Thus, the equation of the tangent line is:

L(x)=807107xL(x) = \frac{80}{7} - \frac{10}{7}x


Do you have questions or need clarification? Here are some related questions to consider:

  1. How do implicit differentiation and product rules work in other contexts?
  2. What is the geometric interpretation of the tangent line at a point?
  3. How do you verify the solution numerically or graphically?
  4. Can this method extend to higher derivatives?
  5. What happens to the solution when the constants in the equation are altered?

Tip: Double-check your substitutions and simplifications to avoid small errors in calculations!

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Math Problem Analysis

Mathematical Concepts

Implicit Differentiation
Tangent Line
Product Rule
Equation of a Line

Formulas

Implicit differentiation: d/dx(f(x, y)) = ∂f/∂x + (∂f/∂y)(dy/dx)
Equation of a line: L(x) = y1 + m(x - x1)

Theorems

Product Rule

Suitable Grade Level

Grade 12 or college-level calculus