Math Problem Statement
find an equation of the tangent line to the curve y at the point. y = 4x sin(x) , (
Solution
To find the equation of the tangent line to the curve at the point , we need two things:
- The derivative of the function , which gives the slope of the tangent line.
- The point on the curve, which we already have as .
Step 1: Find the derivative of
To differentiate , we apply the product rule:
[ \frac{d}{dx}[4x \sin(x)] = \frac{d}{dx}[4x] \cdot \sin(x) + 4x \cdot \frac{d}{dx}[\sin(x)] ]
The derivative of is 4, and the derivative of is . So:
Step 2: Evaluate the derivative at
We substitute into the derivative to find the slope of the tangent line at that point.
Since and , we get:
So, the slope of the tangent line is .
Step 3: Use the point-slope form of the line equation
The point-slope form of the equation of a line is:
Where is the slope and is the point on the line. Substituting , , and :
Step 4: Simplify the equation
Now, we simplify the equation:
Adding to both sides:
Thus, the equation of the tangent line is:
Summary:
The equation of the tangent line to the curve at the point is .
Would you like more details on any of the steps? Or do you have other questions?
5 Follow-up Questions:
- How do you differentiate products of functions (product rule)?
- What does the point-slope form of a line equation look like?
- How can I use the derivative to determine if a function is increasing or decreasing?
- How do I evaluate trigonometric functions like and at key points?
- How can I find the equation of the tangent line for other functions?
Tip: When using the product rule, remember that it applies when you have two functions multiplied together. The rule is: , where and are functions of .
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Math Problem Analysis
Mathematical Concepts
Calculus
Differentiation
Tangent Lines
Trigonometric Functions
Formulas
Product Rule: d/dx[uv] = u'v + uv'
Point-Slope Form of a Line: y - y1 = m(x - x1)
Theorems
Product Rule for differentiation
Point-Slope Formula for a line
Suitable Grade Level
Grades 11-12
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