Math Problem Statement
Use Julia
Use Julia to find the tangent line to the function f(x) = sin(x) at x = π/4. Use tline to calculate the slope (m) and intercept (b).
Solution
It looks like you have provided an image related to a Julia programming exercise involving tangent lines to a function at .
The code example and instructions suggest the following:
- Definition of the function .
- Using
tangent(f, c)
in Julia, where , to calculate the tangent line to . - You are asked to:
- (c) Use the tangent line
tline
to find the intercept by selecting an appropriate value of . - (d) Use
tline
to find the slope of the tangent line.
- (c) Use the tangent line
Explanation:
- The slope of the tangent line is the derivative of at , which is .
- At , . So, the slope is .
- The equation of the tangent line is . To find , use the fact that the line passes through and .
For Julia:
To calculate this:
juliausing MTH229 f(x) = sin(x) c = π/4 tline = tangent(f, c) # Part (c): To find intercept b, choose any value of x # Let's try x = c (π/4): x = π/4 y = tline(x) # Part (d): The slope m is found directly as the output from tline
This will calculate the intercept and slope for the tangent line.
Do you want any further details or clarifications?
Here are five related questions you might explore:
- How does the tangent line change for different values of ?
- Can you derive the equation of the tangent line manually for ?
- What happens if you choose a different function, like ?
- How does the Julia
tangent
function compute the tangent line? - How can you graph the tangent line and the function together in Julia?
Tip: When working with tangents, always remember that the slope is simply the derivative at the point of interest.
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Math Problem Analysis
Mathematical Concepts
Calculus
Tangent Line
Sine Function
Formulas
Tangent Line: y = mx + b
Slope of Tangent: m = f'(x)
f(x) = sin(x)
f'(x) = cos(x)
Theorems
Derivative of trigonometric functions
Slope-intercept form of a line
Suitable Grade Level
Grades 10-12