Math Problem Statement
find the eqution of the line tangent to the graph of y=4lnx at x=3
Solution
To find the equation of the line tangent to the graph of at , we follow these steps:
Step 1: Differentiate the function
The derivative of gives the slope of the tangent line at any point . So, we calculate:
Step 2: Evaluate the slope at
Now, substitute into the derivative to find the slope of the tangent line at this point:
Step 3: Find the point on the curve at
Substitute into the original function to find the corresponding -coordinate:
Using the approximation :
Thus, the point of tangency is .
Step 4: Write the equation of the tangent line
Using the point-slope form of a line equation:
where , , and , we get:
Simplifying the equation:
Thus, the equation of the tangent line is:
Would you like more details or clarifications on any part of this process?
Related Questions:
- How do you find the slope of a curve at any point using derivatives?
- What is the general form of the equation of a tangent line?
- How does the natural logarithmic function affect the shape of a curve?
- Can the derivative of a logarithmic function be extended to include different bases?
- What are other methods to approximate logarithmic values without a calculator?
Tip: Understanding derivatives is key to finding the slopes of tangent lines, which represent instantaneous rates of change.
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Math Problem Analysis
Mathematical Concepts
Calculus
Derivatives
Tangent Line
Logarithmic Functions
Formulas
Derivative of ln(x): d/dx[ln(x)] = 1/x
Point-Slope form of a line: y - y1 = m(x - x1)
Theorems
Derivative of a Logarithmic Function
Suitable Grade Level
Grades 11-12, College Calculus 1