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The graph you've provided shows a periodic function with vertical asymptotes and what appears to be a shape characteristic of a tangent function. The periodicity, asymptotes, and general shape suggest that this function is likely a variation of the tangent function. Let's break down the components.

### Key Observations:
1. **Vertical Asymptotes**: The vertical lines occur at \( t = -\frac{3\pi}{24}, -\frac{\pi}{24}, \frac{\pi}{24}, \frac{3\pi}{24}, \ldots \). These asymptotes suggest that the function involves a tangent or cotangent function, as these functions have vertical asymptotes at regular intervals.

2. **Period**: The distance between consecutive asymptotes is \( \frac{\pi}{12} \), meaning the period of the function is \( \frac{\pi}{12} \).

3. **Amplitude/Scaling**: The graph is vertically scaled, as the values of \( y \) range from \( -5 \) to \( 5 \). This suggests a vertical stretch factor.

4. **Horizontal Shift**: The graph appears to be centered around the origin, with no clear horizontal shift.

### Formula Construction:
The general form for a tangent function is:

\[
y = A \tan(Bt + C) + D
\]

Where:
- \( A \) is the vertical stretch factor (amplitude),
- \( B \) affects the period,
- \( C \) is the horizontal shift,
- \( D \) is the vertical shift.

#### Step-by-Step Formula:
1. **Vertical Stretch**: Since the graph reaches \( y = 5 \) and \( y = -5 \), the vertical stretch factor \( A = 5 \).

2. **Period Adjustment**: The period of the standard tangent function is \( \pi \), but here it is \( \frac{\pi}{12} \). To adjust the period, \( B = 12 \).

3. **Horizontal Shift**: There is no visible horizontal shift in the graph, so \( C = 0 \).

4. **Vertical Shift**: There is no visible vertical shift in the graph, so \( D = 0 \).

### Possible Formula:
\[
y = 5 \tan(12t)
\]

This equation captures the vertical scaling, period, and overall shape of the graph shown.

Would you like further details on any part of the solution, or have any questions?

Here are 5 relative questions for further exploration:
1. How would the formula change if there was a horizontal shift?
2. What if the period was different, say \( \frac{\pi}{6} \)?
3. How would the graph look if the function were cotangent instead of tangent?
4. What effect does changing the vertical stretch \( A \) have on the graph?
5. How does the period of the tangent function relate to its asymptotes?

**Tip**: Always verify the period and range by checking multiple points along the graph to ensure consistency with your function formula.

Give a possible formula for the function shown in the graph.

Learn how to determine the equation of a tangent function with vertical asymptotes and a period of π/12. This step-by-step explanation includes how to adjust for vertical scaling, period, and more. Suitable for students in Grades 10-12.

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