Math Problem Statement
Students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below. Assume that a simple random sample has been selected. Use a 0.10
significance level to test the claim that these times are from a population with a mean equal to 60
seconds. Does it appear that students are reasonably good at estimating one minute? 70 83 39 66 41 21 60 62
65 47 66 69 95 91 67
Question content area bottom Part 1 Perform the test assuming that the requirements are met. Identify the null and alternative hypotheses. Upper H 0 : mu equals 60Upper H 1 : mu not equals 60 (Type integers or decimals. Do not round.) Part 2 Identify the test statistic. enter your response here (Round to two decimal places as needed.)
Solution
To test the claim that the times are from a population with a mean equal to 60 seconds, we'll conduct a one-sample t-test. Here's the step-by-step solution:
Part 1: Hypotheses
The null and alternative hypotheses are:
- Null Hypothesis (): (The mean time is equal to 60 seconds.)
- Alternative Hypothesis (): (The mean time is not equal to 60 seconds.)
Part 2: Test Statistic
First, we need to calculate the sample mean () and the sample standard deviation ().
Given the dataTo test the claim that the times are from a population with a mean equal to 60 seconds, we'll conduct a one-sample t-test. Here's the step-by-step solution:
Part 1: Hypotheses
The null and alternative hypotheses are:
- Null Hypothesis (): (The mean time is equal to 60 seconds.)
- Alternative Hypothesis (): (The mean time is not equal to 60 seconds.)
Part 2: Test Statistic
First, we need to calculate the sample mean () and the sample standard deviation ().
Given the
Step 1: Calculate the sample mean ()
Where:
- (the number of observations)
- is the sum of all observations.
Step 2: Calculate the sample standard deviation ()
Step 3: Calculate the test statistic (t)
Where:
- (the population mean under the null hypothesis)
I'll now calculate these values.### Results:
- Sample Mean (): 62.8 seconds
- Sample Standard Deviation (): 19.68 seconds (rounded to two decimal places)
- Test Statistic (t): 0.55 (rounded to two decimal places)
Conclusion:
Using the calculated test statistic of , you can now compare this with the critical value from the t-distribution table for a two-tailed test at the 0.10 significance level with degrees of freedom, or directly find the p-value associated with this t-statistic.
Do you want to proceed with finding the p-value or critical value to finalize the hypothesis test? Let me know if you need further details!
Here are five related questions you might want to explore:
- How do you determine the degrees of freedom in a t-test?
- What is the p-value, and how do you interpret it?
- How does the significance level affect the outcome of a hypothesis test?
- What assumptions must be met for the t-test to be valid?
- How would the test results change if the sample size were larger?
Tip: When conducting a hypothesis test, always ensure the assumptions (e.g., normality, independence) are reasonably met to validate your results.
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Math Problem Analysis
Mathematical Concepts
Statistics
Hypothesis Testing
T-Test
Formulas
Sample Mean: \(\bar{x} = \frac{\sum x_i}{n}\)
Sample Standard Deviation: \(s = \sqrt{\frac{\sum (x_i - \bar{x})^2}{n-1}}\)
T-Test Statistic: \(t = \frac{\bar{x} - \mu_0}{s/\sqrt{n}}\)
Theorems
Central Limit Theorem
T-Distribution
Suitable Grade Level
Undergraduate Statistics
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