Math Problem Statement

Solve the system of linear equations: 1) x + 5y + 7z = 0 2) x + y + 7z = 4 3) -3y + 7z = 3

Solution

The system of equations in the image is:

1)x+5y+7z=01) \quad x + 5y + 7z = 0 2)x+y+7z=42) \quad x + y + 7z = 4 3)3y+7z=33) \quad -3y + 7z = 3

Solution:

We can solve this system step by step. Let’s start with equation (3):

3y+7z=3-3y + 7z = 3

Solve for yy:

y=7z33y = \frac{7z - 3}{3}

Now substitute this expression for yy into the other two equations.


Substituting into Equation (2):

Substitute y=7z33y = \frac{7z - 3}{3} into the second equation:

x+(7z33)+7z=4x + \left(\frac{7z - 3}{3}\right) + 7z = 4

Multiply through by 3 to eliminate the fraction:

3x+(7z3)+21z=123x + (7z - 3) + 21z = 12

Simplify:

3x+28z3=123x + 28z - 3 = 12 3x+28z=153x + 28z = 15 x=1528z3x = \frac{15 - 28z}{3}


Substituting into Equation (1):

Now substitute y=7z33y = \frac{7z - 3}{3} into the first equation:

x+5(7z33)+7z=0x + 5\left(\frac{7z - 3}{3}\right) + 7z = 0

Multiply through by 3 to eliminate the fraction:

3x+5(7z3)+21z=03x + 5(7z - 3) + 21z = 0 3x+35z15+21z=03x + 35z - 15 + 21z = 0 3x+56z=153x + 56z = 15 x=1556z3x = \frac{15 - 56z}{3}


Now we have two expressions for xx:

x=1528z3x = \frac{15 - 28z}{3} x=1556z3x = \frac{15 - 56z}{3}

Since both equal xx, we can set them equal to each other:

1528z3=1556z3\frac{15 - 28z}{3} = \frac{15 - 56z}{3}

Multiplying both sides by 3:

1528z=1556z15 - 28z = 15 - 56z

Cancel out the 15 on both sides:

28z=56z-28z = -56z

Simplify:

28z=56z28z = 56z

Solve for zz:

z=0z = 0


Now substitute z=0z = 0 back into the expressions for yy and xx:

From y=7z33y = \frac{7z - 3}{3}:

y=7(0)33=1y = \frac{7(0) - 3}{3} = -1

From x=1528z3x = \frac{15 - 28z}{3}:

x=1528(0)3=5x = \frac{15 - 28(0)}{3} = 5


Final Solution:

x=5,y=1,z=0x = 5, \quad y = -1, \quad z = 0

Would you like more details or further explanation?

Related Questions:

  1. How can systems of linear equations be solved using matrices?
  2. What is the method of substitution in solving systems of equations?
  3. Can we solve this system using Gaussian elimination?
  4. How does the determinant of the coefficient matrix affect the solution of a system of equations?
  5. What is Cramer's rule and how does it apply to this system?

Tip:

Always check your solution by substituting the values of the variables back into the original equations to verify correctness.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Substitution Method
Systems of Equations

Formulas

Equation 1: x + 5y + 7z = 0
Equation 2: x + y + 7z = 4
Equation 3: -3y + 7z = 3

Theorems

Substitution Method
Elimination Method

Suitable Grade Level

Grades 9-12