Math Problem Statement

Solution of System of Linear Equations

Nutrition Each ounce of substance A supplies 5% of the nutrition a patient needs. Substance B supplies 15% of the required nutrition per ounce, and substance C supplies 12% of the required nutrition per ounce. If digestive restrictions require that substances A and C be given in equal amounts, and the amount of substance B be one-fifth of either of these other amounts, find the number of ounces of each substance that should be in the meal to provide 100% of the required nutrition.

Solution

Let the number of ounces of substance A be denoted by xx, substance B by yy, and substance C by zz.

Step 1: Set up the equations

We know from the problem:

  1. Substance A supplies 5% of the required nutrition per ounce, so the contribution of substance A is 0.05x0.05x.
  2. Substance B supplies 15% of the required nutrition per ounce, so the contribution of substance B is 0.15y0.15y.
  3. Substance C supplies 12% of the required nutrition per ounce, so the contribution of substance C is 0.12z0.12z.

The total contribution of all three substances must sum to 100%, so:

0.05x + 0.15y + 0.12z = 1 \quad \text{(Equation 1: for 100% nutrition)}

Step 2: Use the given restrictions

  • First restriction: Substances A and C must be given in equal amounts: x=z(Equation 2)x = z \quad \text{(Equation 2)}

  • Second restriction: The amount of substance B must be one-fifth of either of the amounts of A or C: y=15x(Equation 3)y = \frac{1}{5}x \quad \text{(Equation 3)}

Step 3: Substitute the restrictions into Equation 1

Using x=zx = z and y=15xy = \frac{1}{5}x, substitute into Equation 1:

0.05x+0.15(15x)+0.12x=10.05x + 0.15\left(\frac{1}{5}x\right) + 0.12x = 1

Step 4: Simplify the equation

Simplify the terms:

0.05x+0.15×15x+0.12x=10.05x + 0.15 \times \frac{1}{5}x + 0.12x = 1 0.05x+0.03x+0.12x=10.05x + 0.03x + 0.12x = 1 0.20x=10.20x = 1

Step 5: Solve for xx

x=10.20=5x = \frac{1}{0.20} = 5

Step 6: Find yy and zz

From x=zx = z, we know that: z=5z = 5

From y=15xy = \frac{1}{5}x, we know that: y=15×5=1y = \frac{1}{5} \times 5 = 1

Final Answer

The number of ounces of each substance is:

  • Substance A: 55 ounces
  • Substance B: 11 ounce
  • Substance C: 55 ounces

Would you like further details or have any questions? Here are some related questions:

  1. What happens if the nutrition requirements change for one of the substances?
  2. How would the system change if substances A and C didn’t have to be equal?
  3. How can you express the problem using matrices?
  4. What if substance B had a different percentage contribution?
  5. How can you verify the solution using substitution?

Tip: Always check that all constraints are satisfied when solving a system of linear equations!

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Equations
System of Equations

Formulas

0.05x + 0.15y + 0.12z = 1
x = z
y = (1/5)x

Theorems

Substitution Method in solving systems of linear equations

Suitable Grade Level

Grades 9-12