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To calculate the surface area of the right rectangular prism, we need to determine the area of each of its faces and sum them up. The net provided shows six faces of the prism, corresponding to three distinct pairs of identical rectangles.

### Step 1: Identify the dimensions of the prism
From the net:
- The length (l) is 13 meters (the longer horizontal side).
- The width (w) is 11 meters (the vertical side).
- The height (h) is 7 meters (the smaller horizontal side).

### Step 2: Calculate the area of each face
The rectangular prism has three distinct sets of opposite faces, which means the surface area will be:
\[
\text{Surface Area} = 2lw + 2lh + 2wh
\]

1. **Two faces with dimensions length × width**:
   \[
   A_1 = 2 \times (13 \times 11) = 2 \times 143 = 286 \, \text{m}^2
   \]

2. **Two faces with dimensions length × height**:
   \[
   A_2 = 2 \times (13 \times 7) = 2 \times 91 = 182 \, \text{m}^2
   \]

3. **Two faces with dimensions width × height**:
   \[
   A_3 = 2 \times (11 \times 7) = 2 \times 77 = 154 \, \text{m}^2
   \]

### Step 3: Sum all the areas
\[
\text{Total Surface Area} = A_1 + A_2 + A_3 = 286 + 182 + 154 = 622 \, \text{m}^2
\]

Thus, the surface area of the right rectangular prism is **622 square meters**.

Would you like more details, or do you have any questions?

### Related Questions:
1. How do you calculate the volume of this rectangular prism?
2. What is the relationship between surface area and volume in 3D shapes?
3. How would changing the height affect the surface area?
4. What is the formula for the surface area of a general prism?
5. How can you check if two prisms have the same surface area but different volumes?

### Tip:
Always break down complex 3D shapes into simpler 2D shapes to make surface area calculations easier!

The figure below is a net for a right rectangular prism. What is the surface area of the right rectangular prism, in square meters?

Learn how to calculate the surface area of a right rectangular prism with dimensions 13 meters by 11 meters by 7 meters. This geometry problem covers surface area formulas and is suitable for students in Grades 6-8.

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