To calculate the surface area of the cuboid from the provided net, we need to determine the area of each rectangle in the net and then sum them up.

The dimensions of the cuboid are:

• Length = 5 cm
• Width = 3 cm
• Height = 2 cm

The net consists of 6 rectangles:

1. 2 rectangles with dimensions 5 cm × 3 cm

   • Area of each = $5 \times 3 = 15 \, \text{cm}^2$
   • Total area for these two = $2 \times 15 = 30 \, \text{cm}^2$

2. 2 rectangles with dimensions 5 cm × 2 cm

   • Area of each = $5 \times 2 = 10 \, \text{cm}^2$
   • Total area for these two = $2 \times 10 = 20 \, \text{cm}^2$

3. 2 rectangles with dimensions 3 cm × 2 cm

   • Area of each = $3 \times 2 = 6 \, \text{cm}^2$
   • Total area for these two = $2 \times 6 = 12 \, \text{cm}^2$

Now, summing all these areas: $30 + 20 + 12 = 62 \, \text{cm}^2$

Thus, the surface area of the cuboid is 62 cm².

Would you like more details or further clarification?

Here are 5 related questions to consider:

1. How would the surface area change if the dimensions were doubled?
2. What is the formula for the surface area of a general cuboid?
3. How would you find the volume of this cuboid?
4. Can the net of a cuboid be arranged differently while maintaining the same surface area?
5. How can you distinguish a cube from a cuboid based on the net?

Tip: When calculating surface area from a net, ensure you correctly pair up corresponding faces of the cuboid.