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### Solution:

The given problem involves finding the **surface area** of a cube, given the length of its **diagonal**. Here's the step-by-step breakdown:

---

#### Step 1: Relationship Between Diagonal and Side Length of a Cube
For a cube with side length \(a\), the space diagonal (\(d\)) is related to \(a\) by the formula:
\[
d = a\sqrt{3}.
\]

Here, the diagonal is given as \(\sqrt{12}\). Using the formula above:
\[
\sqrt{12} = a\sqrt{3}.
\]

---

#### Step 2: Solve for \(a\)
Divide both sides by \(\sqrt{3}\):
\[
a = \frac{\sqrt{12}}{\sqrt{3}}.
\]

Simplify the fraction:
\[
a = \sqrt{\frac{12}{3}} = \sqrt{4} = 2.
\]

Thus, the side length of the cube is \(a = 2\).

---

#### Step 3: Calculate the Surface Area of the Cube
The surface area of a cube is given by:
\[
\text{Surface Area} = 6a^2.
\]

Substitute \(a = 2\):
\[
\text{Surface Area} = 6(2^2) = 6(4) = 24.
\]

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### Final Answer:
The surface area of the cube is **24 square units**.

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Would you like further explanation on any part of the solution? Here are some additional questions for practice:

1. If the side length of a cube is \(3\), what is its space diagonal?
2. How is the volume of a cube calculated, and what would the volume be for a cube with side length \(2\)?
3. What is the relationship between the face diagonal and the side length of a cube?
4. If the diagonal of a cube is doubled, by what factor does the surface area increase?
5. Derive the formula for the space diagonal of a cube.

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**Tip**: Always break down 3D geometry problems into their basic 2D components (e.g., diagonals and side lengths) for easier calculation!

The diagram below shows one diagonal of a cube. If the length of the diagonal is √12 units, then the surface area of the cube is?

Find the surface area of a cube with a diagonal of √12 units using geometric formulas. This problem covers 3D geometry concepts, including the relationship between a cube's diagonal and its side length, and is suitable for students in Grades 8-10.

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