Math Problem Statement

one a graph Are point points : (6, 10)(5, 7)(4, 3)(3, 6)(2, 2) and a straight line with x intercept on 1 and these pints : (2, 2)°(6, 10) What is the observed value of at x=5 2. What is the predicted value of at x=3 3. Find the sum of the residual values of the five points from line. 4. Find the sum of the squares of the deviations of the five points from line.

Solution

To solve this problem, let's break down the steps:

1. The Equation of the Line

You mentioned a straight line with:

  • xx-intercept at x=1x = 1
  • Passing through points (2,2)(2, 2) and (6,10)(6, 10)

Step 1: Find the slope of the line.

The slope mm is calculated using the two points (2,2)(2, 2) and (6,10)(6, 10): m=y2y1x2x1=10262=84=2m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{10 - 2}{6 - 2} = \frac{8}{4} = 2

Step 2: Find the equation of the line.

Using the point-slope form yy1=m(xx1)y - y_1 = m(x - x_1) with (2,2)(2, 2) and slope m=2m = 2: y2=2(x2)y - 2 = 2(x - 2) y2=2x4y - 2 = 2x - 4 y=2x2y = 2x - 2

Thus, the equation of the line is: y=2x2y = 2x - 2

2. Observed and Predicted Values

Next, let's calculate the observed and predicted values at the given points.

2.1. Observed Value at x=5x = 5:

From the table of given points, the observed value at x=5x = 5 is y=7y = 7.

2.2. Predicted Value at x=3x = 3:

Using the line equation y=2x2y = 2x - 2, substitute x=3x = 3: y=2(3)2=62=4y = 2(3) - 2 = 6 - 2 = 4 So, the predicted value at x=3x = 3 is y=4y = 4.

3. Sum of the Residuals

The residual for each point is the difference between the observed yy-value and the predicted yy-value from the line.

xxObserved yyPredicted y=2x2y = 2x - 2Residual (Observed - Predicted)
6102(6)2=102(6) - 2 = 101010=010 - 10 = 0
572(5)2=82(5) - 2 = 878=17 - 8 = -1
432(4)2=62(4) - 2 = 636=33 - 6 = -3
362(3)2=42(3) - 2 = 464=26 - 4 = 2
222(2)2=22(2) - 2 = 222=02 - 2 = 0

Sum of residuals: 0+(1)+(3)+2+0=20 + (-1) + (-3) + 2 + 0 = -2 So, the sum of the residuals is 2-2.

4. Sum of the Squares of the Deviations

To find the sum of the squares of the residuals, we square each residual value.

ResidualSquared Residual
00
-11
-39
24
00

Sum of squared residuals: 0+1+9+4+0=140 + 1 + 9 + 4 + 0 = 14 So, the sum of the squares of the deviations is 1414.

Summary of Results:

  1. Observed value at x=5x = 5: 77
  2. Predicted value at x=3x = 3: 44
  3. Sum of the residuals: 2-2
  4. Sum of the squares of the deviations: 1414

Would you like further clarification on any of the steps? Here are some related questions:

  1. How do you find the equation of a line given two points?
  2. What is the significance of the residual in regression analysis?
  3. How are residuals used to measure the accuracy of a model?
  4. How do we interpret the sum of residuals when it’s non-zero?
  5. Why do we square residuals when calculating deviations?

Tip: When summing residuals, a value close to zero indicates that the line is a good fit for the data.

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Math Problem Analysis

Mathematical Concepts

Linear Equations
Slope-Intercept Form
Residuals
Deviation

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Line equation: y = mx + b
Residual = Observed - Predicted
Sum of Squared Deviations = Σ(residual^2)

Theorems

Slope-Intercept Form

Suitable Grade Level

Grades 8-10