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The problem states: 

**"The sum of three consecutive numbers is 72. What are the three numbers?"**

Let's solve this step by step.

### Step 1: Define the three consecutive numbers
Let the three consecutive numbers be:
- \( x \) (the first number),
- \( x + 1 \) (the second number),
- \( x + 2 \) (the third number).

### Step 2: Set up the equation
The sum of these three numbers is given as 72:
\[
x + (x + 1) + (x + 2) = 72
\]

### Step 3: Simplify the equation
Combine the like terms:
\[
3x + 3 = 72
\]

### Step 4: Solve for \( x \)
Subtract 3 from both sides:
\[
3x = 69
\]
Now, divide both sides by 3:
\[
x = 23
\]

### Step 5: Find the three consecutive numbers
If \( x = 23 \), then the three consecutive numbers are:
- First number: \( x = 23 \)
- Second number: \( x + 1 = 24 \)
- Third number: \( x + 2 = 25 \)

So, the three consecutive numbers are **23, 24, and 25**.

Would you like further details or explanations? 

Here are five related questions that you might find helpful:
1. What would the three consecutive numbers be if their sum was 90?
2. How would the problem change if the numbers were consecutive even numbers?
3. What is the sum of four consecutive numbers if the smallest number is 10?
4. How do you set up an equation for the sum of consecutive odd numbers?
5. What is the product of three consecutive numbers if their sum is 72?

**Tip:** When dealing with consecutive numbers in algebra, always express them in terms of a single variable and its increments to simplify the problem.

The sum of three consecutive numbers is 72. What are the three numbers?

Learn how to solve the problem of finding three consecutive numbers whose sum is 72. This algebraic problem covers key concepts related to linear equations and is suitable for students in Grades 6-8.

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