∑ 1/( sqrt(n)) + 1/( sqrt(n+1)) solve this don't need any explanation

from sympy import symbols, sqrt, summation

# Define variable
n = symbols('n', integer=True)

# Expression inside the sum
expr = 1/sqrt(n) + 1/sqrt(n + 1)

# Compute the summation (assuming summing from n=1 to some upper limit N, say N=10)
N = 10
result = summation(expr, (n, 1, N))
resultThe result of the summation \( \sum_{n=1}^{10} \left( \frac{1}{\sqrt{n}} + \frac{1}{\sqrt{n+1}} \right) \) is:

\[
\frac{\sqrt{11}}{11} + \frac{\sqrt{10}}{5} + \frac{2\sqrt{7}}{7} + \frac{\sqrt{6}}

Explore the sum of the series 1/(sqrt(n)) + 1/(sqrt(n+1)) with a step-by-step solution. This problem involves series and limits in mathematics, suitable for advanced high school students and beyond.

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