Math Problem Statement

The number N = 242024 + 242025 has some factors between 1 and 25. What is the sum of all those integers between 1 and 25 which are not factors of N?

Solution

The problem asks for the sum of all integers between 1 and 25 that are not factors of NN, where:

N=242024+242025N = 242024 + 242025

Step 1: Simplify NN

N=242024+242025=484049N = 242024 + 242025 = 484049

Step 2: Determine the factors of NN between 1 and 25

We need to check which integers from 1 to 25 divide N=484049N = 484049 without a remainder.

Step 3: Verify NN's divisors between 1 and 25

The prime factorization or divisors can be tested systematically. However, for practical purposes:

  1. N=484049N = 484049 is 6952695^2, a perfect square. Hence, its divisors are based on 6952695^2.

We note factors! ProceedLet’s carefully analyze the given problem:

Step 1: Compute NN

N=242024+242025=484049.N = 242024 + 242025 = 484049.

This simplifies NN as:

N=6952(because 695×695=484049).N = 695^2 \, (\text{because } 695 \times 695 = 484049).

Step 2: Factors of NN

The number N=6952N = 695^2 has divisors that include 1, 695, and 484049, among others. To find factors of NN specifically between 1 and 25, we test each integer from 1 to 25 to see if it divides NN without remainder.

Step 3: Divisors of NN between 1 and 25

We systematically test each number from 1 to 25:

  • 11: Always a factor.
  • 2,3,4,5,6,,24,252, 3, 4, 5, 6, \dots, 24, 25: None of these are factors because 695695 is odd, and its prime factors are not divisible by 2, 3, or 5. Therefore, only 1 is a factor of NN in this range.

Step 4: Integers NOT factors of NN

The integers between 1 and 25 are: {1,2,3,4,,25}.\{1, 2, 3, 4, \dots, 25\}.

Since only 1 is a factor, the numbers not factors of NN are: {2,3,4,5,,25}.\{2, 3, 4, 5, \dots, 25\}.

Step 5: Sum of integers not factors of NN

The sum of integers from 1 to 25 is: Sum=25×262=325.\text{Sum} = \frac{25 \times 26}{2} = 325.

Subtract the factor 11: 3251=324.325 - 1 = 324.

Final Answer:

The sum of all integers between 1 and 25 that are not factors of NN is: 324.\boxed{324}.

Would you like further clarification or a deeper breakdown?


Here are 5 related questions for exploration:

  1. How can you systematically determine all factors of a number?
  2. Why does the prime factorization of a number help identify divisors?
  3. What is the significance of 6952695^2 in the factorization process?
  4. How would the sum change if the range of integers was extended to 50?
  5. How do perfect squares impact the calculation of factors?

Tip: Always check for prime factorization when analyzing divisors—it simplifies the process significantly!

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Math Problem Analysis

Mathematical Concepts

Arithmetic
Number Theory
Divisors

Formulas

Sum of first n natural numbers: (n × (n + 1)) / 2

Theorems

Properties of divisors and factors of numbers

Suitable Grade Level

Grades 9-12