Math Problem Statement

Find the sum of the convergent series: 6 + 0.6 + 0.06 + 0.006 + ...

Solution

This image contains a geometric series:

6+0.6+0.06+0.006+6 + 0.6 + 0.06 + 0.006 + \dots

This is a geometric series where the first term a=6a = 6 and the common ratio r=0.1r = 0.1 (since each term is 1/10 of the previous one).

The sum SS of an infinite geometric series can be found using the formula:

S=a1rS = \frac{a}{1 - r}

where r<1|r| < 1.

Substituting the given values:

S=610.1=60.9=609=6.6667S = \frac{6}{1 - 0.1} = \frac{6}{0.9} = \frac{60}{9} = 6.6667

Thus, the sum of the convergent series is approximately:

S=6.6667S = 6.6667

Would you like more details on the steps, or do you have any specific questions?

Here are 5 related questions:

  1. How does the value of rr affect the convergence of a geometric series?
  2. What happens if the common ratio r1r \geq 1?
  3. Can you derive the formula for the sum of an infinite geometric series?
  4. What if the first term aa were different? How would it change the sum?
  5. How do we know this series is geometric and not arithmetic?

Tip: Always check if the common ratio in a geometric series satisfies r<1|r| < 1, as this guarantees the series converges.

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Math Problem Analysis

Mathematical Concepts

Geometric Series
Convergent Series

Formulas

S = a / (1 - r) for an infinite geometric series

Theorems

Geometric series sum formula for |r| < 1

Suitable Grade Level

Grades 10-12