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To find the sum of the complex numbers in the expression:

\[
[(-3 + 2i) - (5 - 6i) + (9 - 6i)]
\]

we will break it down step-by-step.

### Step 1: Distribute the negative sign for \((5 - 6i)\)
\[
- (5 - 6i) = -5 + 6i
\]

So, we rewrite the expression as:
\[
(-3 + 2i) + (-5 + 6i) + (9 - 6i)
\]

### Step 2: Combine the real parts
The real parts are \(-3\), \(-5\), and \(9\):
\[
-3 - 5 + 9 = 1
\]

### Step 3: Combine the imaginary parts
The imaginary parts are \(2i\), \(6i\), and \(-6i\):
\[
2i + 6i - 6i = 2i
\]

### Final Answer
Putting it all together, we get:
\[
1 + 2i
\]

So, the sum is:

\[
\boxed{1 + 2i}
\]

Would you like further details, or do you have any questions?

Here are some related questions for additional practice:
1. How do you add and subtract complex numbers in general?
2. What is the result of multiplying two complex numbers?
3. How would you express the complex number \((3 + 4i)\) in polar form?
4. What is the complex conjugate of \((5 - 3i)\) and how is it used?
5. How does dividing complex numbers differ from adding or subtracting them?

**Tip:** Remember to always group real and imaginary terms separately when adding or subtracting complex numbers.

Find the sum of [(-3 + 2i) - (5 - 6i) + (9 - 6i)].

Learn how to find the sum of complex numbers in the expression [(-3 + 2i) - (5 - 6i) + (9 - 6i)] with a step-by-step solution. This problem covers key concepts in complex number operations and is suitable for students in Grades 9-12.

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