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To solve this problem, we need to compute the sum of the additive inverse of two fractions: \(-\frac{3}{8}\) and \(-\frac{4}{8}\).

1. **Additive Inverse**: The additive inverse of a number is what you add to that number to get zero. For any number \(x\), the additive inverse is \(-x\). In simpler terms, you just change the sign of the number.
   - The additive inverse of \(-\frac{3}{8}\) is \(\frac{3}{8}\).
   - The additive inverse of \(-\frac{4}{8}\) is \(\frac{4}{8}\).

2. **Sum of the Additive Inverses**: Now, sum the two additive inverses:
   \[
   \frac{3}{8} + \frac{4}{8} = \frac{7}{8}
   \]

Therefore, the correct answer is **A) \(\frac{7}{8}\)**.

Would you like further explanation or have any other questions?

Here are 5 related questions:
1. What is the additive inverse of \( \frac{5}{7} \)?
2. How do you find the additive inverse of a negative number?
3. What is the result when you add the additive inverse of two fractions with unlike denominators?
4. How do you simplify the sum of two fractions?
5. What is the relationship between additive inverses and zero?

**Tip**: To find the additive inverse of any fraction, simply change its sign.

Sum of the additive inverse of -3/8 and the additive inverse of -4/8 is equal to:

Find the sum of the additive inverses of -3/8 and -4/8 with a step-by-step solution. This problem explores the additive inverse property and fraction arithmetic, suitable for students in Grades 6-8.

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