Let the four consecutive integers be represented as $x$, $x+1$, $x+2$, and $x+3$.

The sum of these integers is given by:

$x + (x+1) + (x+2) + (x+3) = -106$

Simplifying the left-hand side:

$4x + 6 = -106$

Now, subtract 6 from both sides:

$4x = -106 - 6$ $4x = -112$

Next, divide both sides by 4:

$x = \frac{-112}{4} = -28$

So, the first integer is $x = -28$.

The four consecutive integers are:

$-28, -27, -26, -25$

Finally, we can check the sum:

$-28 + (-27) + (-26) + (-25) = -106$

Thus, the solution is correct.

Would you like more details or have any questions?

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Here are 5 related questions to explore further:

1. What is the sum of 5 consecutive integers if the middle one is -10?
2. How do you express the sum of any $n$ consecutive integers algebraically?
3. What is the sum of the first 20 consecutive positive integers?
4. Can the sum of 3 consecutive integers be a positive even number?
5. What is the sum of 4 consecutive odd integers?

Tip: The sum of consecutive integers can be quickly computed using basic algebra, as the numbers follow a predictable linear pattern.