Math Problem Statement

Determine the sum of the first seven terms of the geometric series in which (t1= 13 and r = 5)

Solution

To find the sum of the first seven terms of a geometric series, we use the formula:

Sn=t11rn1rS_n = t_1 \frac{1 - r^n}{1 - r}

Where:

  • SnS_n is the sum of the first nn terms,
  • t1t_1 is the first term of the series,
  • rr is the common ratio,
  • nn is the number of terms.

Given:

  • t1=13t_1 = 13,
  • r=5r = 5,
  • n=7n = 7.

Let's substitute the values into the formula:

S7=13×15715S_7 = 13 \times \frac{1 - 5^7}{1 - 5}

First, calculate 575^7:

57=781255^7 = 78125

Now substitute:

S7=13×17812515S_7 = 13 \times \frac{1 - 78125}{1 - 5}

S7=13×781244S_7 = 13 \times \frac{-78124}{-4}

Simplify:

S7=13×19531S_7 = 13 \times 19531

Now multiply:

S7=253903S_7 = 253903

Thus, the sum of the first seven terms of the geometric series is 253903\boxed{253903}.

Would you like further details or have any questions?

Here are 5 related questions to explore further:

  1. How do you find the sum of an infinite geometric series?
  2. What happens to the sum of the geometric series if the common ratio rr is less than 1?
  3. Can you derive the sum formula for a geometric series?
  4. How does the number of terms affect the sum of a geometric series?
  5. How can geometric series be applied in real-life scenarios?

Tip: When the common ratio rr is between -1 and

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Math Problem Analysis

Mathematical Concepts

Geometric Series
Exponents
Sequences and Series

Formulas

Sn = t1 * (1 - r^n) / (1 - r)

Theorems

Geometric Series Sum Formula

Suitable Grade Level

Grades 9-12