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The given chemical reaction is:

\[
\text{Zn} + 2\text{HCl} \rightarrow \text{H}_2 + \text{ZnCl}_2
\]

This balanced chemical equation tells us that 1 mole of Zinc (Zn) reacts with 2 moles of Hydrochloric Acid (HCl) to produce 1 mole of Hydrogen gas (H₂).

Now, the problem asks for the number of moles of H₂ released when 3 moles of Zn react completely with HCl.

From the balanced equation, we know that:

- 1 mole of Zn produces 1 mole of H₂.

Therefore, if 3 moles of Zn react completely:

\[
3 \text{ moles of Zn} \times \frac{1 \text{ mole of H}_2}{1 \text{ mole of Zn}} = 3 \text{ moles of H}_2
\]

So, **3 moles of H₂** are released.

Would you like further details or have any questions?

Here are 5 follow-up questions based on this:

1. How many moles of HCl would be required to react with 3 moles of Zn?
2. What mass of Zn would be needed to produce 3 moles of H₂?
3. How many grams of H₂ are produced if 3 moles are released?
4. What is the molar mass of Zn and H₂?
5. What would happen if only 2 moles of Zn were used instead of 3?

**Tip:** Always check that a chemical equation is balanced before performing stoichiometric calculations, as this ensures that the mole ratios are correct.

What number of moles of H₂ are released when 3 moles of Zn completely react with HCl? Zn + 2HCl → H₂ + ZnCl₂

Learn how to calculate the number of moles of hydrogen gas (H₂) released when 3 moles of Zinc (Zn) completely react with Hydrochloric Acid (HCl). This problem uses key stoichiometric concepts and balanced chemical equations, ideal for high school students.

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