Math Problem Statement
Solve this friction problem
Solution
To solve this problem, let’s break down the forces and analyze the static equilibrium conditions. Here’s a step-by-step guide.
Problem Information:
- Weight of crate, lbs
- Distance to center of gravity from base : ft vertically.
- Dimensions of crate: ft tall and ft wide.
- Coefficient of static friction .
- Goal: Find the maximum horizontal force that can be applied without causing movement.
Steps for Solution
-
Identify forces and moments:
- The crate is in static equilibrium, so the sum of all forces and moments must equal zero.
- There are three forces acting on the crate:
- The applied force horizontally at the upper left corner.
- The weight lbs acting downwards at point .
- The normal force acting upwards at point .
- There’s also a frictional force at point , which resists the horizontal motion and is given by .
-
Set up equilibrium equations:
Sum of Forces in the Vertical Direction ( ):
Sum of Forces in the Horizontal Direction ( ):
-
Moment about Point : To ensure the crate doesn’t tip over, take moments about point .
Moment Equation:
- The clockwise moment caused by is:
- The counterclockwise moment due to the weight at the center of gravity is: Setting the moments equal for static equilibrium:
-
Conclusion: The limiting factor for the applied force is the tipping moment, giving us:
So, the maximum force that can be applied to the crate without causing movement is 83.33 lbs.
Would you like further explanation or have any questions?
Related Questions:
- How does the coefficient of friction affect the maximum force in this scenario?
- What would happen if the crate's weight increased? How would that change the maximum force ?
- How would the result change if the force were applied lower on the crate?
- What role does the center of gravity play in determining tipping risk in static equilibrium problems?
- How does the width of the crate affect the tipping point calculation?
Tip:
When solving static equilibrium problems, always start by identifying all forces, establishing coordinate axes, and writing down equilibrium equations for both forces and moments.
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Math Problem Analysis
Mathematical Concepts
Statics
Friction
Equilibrium
Moments
Formulas
f = μ_s * N (frictional force)
ΣF_x = 0 (horizontal force balance)
ΣF_y = 0 (vertical force balance)
ΣM_A = 0 (moment equilibrium at point A)
Theorems
Static Equilibrium: ΣF = 0 and ΣM = 0
Moment about a point
Suitable Grade Level
Undergraduate Engineering (Statics or Physics)
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