Math Problem Statement

give the standard form given the information of ellipse. foci at positive and negative 2 and vertex at (-7/2, 0)

Solution

The given ellipse has foci at (2,0)(2, 0) and (2,0)(-2, 0), which suggests that the ellipse is centered at the origin and is horizontally oriented. Additionally, you mentioned that one of the vertices is at (72,0)(-\frac{7}{2}, 0). This gives us enough information to find the standard form of the equation of the ellipse.

Let's outline the process:

Step 1: Standard Form of an Ellipse

The standard form of the equation of an ellipse centered at the origin is:

x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1

Where:

  • aa is the semi-major axis (distance from the center to the vertex).
  • bb is the semi-minor axis.
  • cc is the distance from the center to the foci.

Step 2: Find cc

From the information given, the foci are at (2,0)(2, 0) and (2,0)(-2, 0). The distance from the center to either focus is c=2c = 2.

Step 3: Find aa

The vertex is at (72,0)(-\frac{7}{2}, 0), which means the distance from the center to the vertex is a=72a = \frac{7}{2}.

Step 4: Relationship Between aa, bb, and cc

For an ellipse, the relationship between aa, bb, and cc is:

c2=a2b2c^2 = a^2 - b^2

Substituting c=2c = 2 and a=72a = \frac{7}{2}:

22=(72)2b22^2 = \left( \frac{7}{2} \right)^2 - b^2

4=494b24 = \frac{49}{4} - b^2

Step 5: Solve for b2b^2

Multiply the entire equation by 4 to eliminate the fraction:

16=494b216 = 49 - 4b^2

4b2=334b^2 = 33

b2=334b^2 = \frac{33}{4}

Step 6: Write the Equation

Now that we have a2=(72)2=494a^2 = \left( \frac{7}{2} \right)^2 = \frac{49}{4} and b2=334b^2 = \frac{33}{4}, we can plug these values into the standard form of the ellipse equation:

x2494+y2334=1\frac{x^2}{\frac{49}{4}} + \frac{y^2}{\frac{33}{4}} = 1

Simplifying:

4x249+4y233=1\frac{4x^2}{49} + \frac{4y^2}{33} = 1

This is the standard form of the ellipse.


Would you like more details or have any questions? Here are five related questions to explore this further:

  1. How do you determine whether an ellipse is horizontal or vertical?
  2. How can you find the eccentricity of an ellipse?
  3. What is the geometric significance of the foci in an ellipse?
  4. How does the equation change if the ellipse is centered at a point other than the origin?
  5. How do you calculate the area of an ellipse?

Tip: Always remember the relationship c2=a2b2c^2 = a^2 - b^2 when dealing with ellipses.

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Math Problem Analysis

Mathematical Concepts

Conic Sections
Ellipses

Formulas

Standard form of an ellipse: x^2/a^2 + y^2/b^2 = 1
Relationship between semi-major axis (a), semi-minor axis (b), and foci (c): c^2 = a^2 - b^2

Theorems

Ellipse Geometry

Suitable Grade Level

Grades 10-12