Math Problem Statement

x 51 55 49 79 45 37 69 45 48 y 150 48 24 35 36 171 15 185 27 What is the value of se for this data set? (Round your answer to five decimal places.)

Solution

To calculate the standard error of the estimate (denoted as ses_e) for this data set, we follow these steps:

Step 1: Calculate the Regression Line

The standard error of the estimate is related to the regression line equation: y=a+bxy = a + bx where bb is the slope and aa is the y-intercept. The formula for bb (slope) and aa (intercept) are:

b=nxiyixiyinxi2(xi)2b = \frac{n \sum{x_iy_i} - \sum{x_i}\sum{y_i}}{n \sum{x_i^2} - (\sum{x_i})^2} a=yibxina = \frac{\sum{y_i} - b \sum{x_i}}{n}

Where:

  • xix_i and yiy_i are the data points for xx and yy
  • nn is the number of data points

Step 2: Compute the Predicted yy-values

Once we have the regression equation y=a+bxy = a + bx, we can compute the predicted values of yy (denoted as y^i\hat{y}_i) for each xix_i.

Step 3: Compute the Residuals

The residuals are the differences between the observed and predicted values of yy: ei=yiy^ie_i = y_i - \hat{y}_i

Step 4: Calculate ses_e (Standard Error of the Estimate)

The formula for ses_e is: se=ei2n2s_e = \sqrt{\frac{\sum{e_i^2}}{n - 2}} where ei2\sum{e_i^2} is the sum of the squared residuals and nn is the number of data points.


I'll now perform these calculations step by step using the provided data to find ses_e. Let me compute the necessary values. numpy as np

Data points

x = np.array([51, 55, 49, 79, 45, 37, 69, 45, 48]) y = np.array([150, 48, 24, 35, 36, 171, 15, 185, 27])

Number of data points

n = len(x)

Step 1: Calculate the sums needed for the regression coefficients

sum_x = np.sum(x) sum_y = np.sum(y) sum_x_squared = np.sum(x**2) sum_xy = np.sum(x * y)

Step 2: Calculate the slope (b) and intercept (a)

b = (n * sum_xy - sum_x * sum_y) / (n * sum_x_squared - sum_x**2) a = (sum_y - b * sum_x) / n

Step 3: Calculate the predicted y values (y-hat) and residuals (e_i)

y_pred = a + b * x residuals = y - y_pred

Step 4: Calculate the standard error of the estimate (s_e)

sum_squared_residuals = np.sum(residuals**2) s_e = np.sqrt(sum_squared_residuals / (n - 2))

s_eThe standard error of the estimate (denoted as ses_e) for this data set is approximately 63.60425 (rounded to five decimal places).

Would you like further details on the calculations or any other aspect of the problem?

Here are some related questions you might find useful:

  1. How do you calculate the correlation coefficient rr for this data set?
  2. What does the slope bb represent in a regression analysis?
  3. How can you interpret the residuals in a regression model?
  4. What is the coefficient of determination (R2R^2) and how is it calculated?
  5. How does the standard error of the estimate help assess the fit of the regression line?

Tip: To improve the fit of a regression model, you can try transforming the variables (e.g., log transformation) if the relationship between xx and yy seems non-linear.

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Math Problem Analysis

Mathematical Concepts

Regression Analysis
Standard Error of the Estimate

Formulas

y = a + bx
b = (n Σx_i y_i - Σx_i Σy_i) / (n Σx_i^2 - (Σx_i)^2)
a = (Σy_i - b Σx_i) / n
e_i = y_i - ŷ_i
se = √(Σe_i^2 / (n - 2))

Theorems

Regression Line
Standard Error of the Estimate

Suitable Grade Level

College (Introductory Statistics)